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Svet_ta [14]
3 years ago
6

Compare fractions 3/4 and 11/12

Mathematics
1 answer:
RoseWind [281]3 years ago
5 0

For now, assume 3/4 and 11/12 are equal. It is likely they are not equal, but we'll get to that later.

The equation we set up is 3/4 = 11/12

---------------------------------------------------------------

3/4 = 11/12

3*12 = 4*11 ... cross multiply

36 = 44

The last equation is false, so the entire string of equations are false.

This tells us that 3/4 is not equal to 11/12.

Since the left hand side of the last equation is smaller, this means we must replace the equal sign with a less than sign. Do so with the other equal signs as well. We have this updated set of steps

3/4 < 11/12

3*12 < 4*11 ... cross multiply

36 < 44

We see that 3/4 is smaller than 11/12

---------------------------------------------------------------

Another way to see that 3/4 is smaller is to use a calculator to find the decimal version of each fraction

3/4 = 0.75

11/12 = 0.9167 approximately

Since 0.75 is smaller than 0.9167, this means 3/4 is smaller than 11/12.

---------------------------------------------------------------

If you want to stick with fractions and you don't want to cross multiply, then we can rewrite 3/4 as a fraction that has 12 in the denominator.

Multiply top and bottom of 3/4 by the value 3

This will make 3/4 turn into 9/12

3*3 = 9

4*3 = 12

So 3/4 = 9/12 is a true equation

Instead of comparing "3/4 and 11/12", we are equivalently comparing "9/12 and 11/12".

The numerator 9 is smaller than the numerator 11, so 9/12 is smaller than 11/12

This points to 3/4 being smaller than 11/12.

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1 year ago
Factor the expression 8x^3y-8x^2y-30xy
miv72 [106K]

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GCF = 2xy

Factor out the GCF. (Write the GCF first. Then, in parentheses, divide each term by the GCF.)

2xy(8x^3y/2xy + -8x^2y/2xy + -30xy/2xy)

Simplify each term in parenthesis

2xy(4x^2 - 4x - 15)

Split the second term in 4x^2 - 4x - 15 into two terms

2xy(4x^2 + 6x - 10x - 15)

Factor out common terms in the first two terms, then in the last two terms;

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Factor out the common term 2x + 3

<u>= 2xy(2x + 3)(2x - 5)</u>

4 0
3 years ago
3x + 5y=32 2x + 3y=23 solve by elimintaion method
algol [13]

Answer:

x=19, y=-5

Step-by-step explanation:

Add the equations in order to solve for the first variable. Plug this value into the other equations in order to solve for the remaining variables.

Point Form:

(19, -5)

Equation Form:

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Hope this helps.

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2 years ago
How much solutions does this equation have?
Evgesh-ka [11]

Answer:

All solutions or infinite.

Step-by-step explanation:

Turn 2y = -4x + 6 into standard form - divide by 2

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Substitute the y equation in for y.

2x - 2x + 3 = 3

The x variables cancel out.

3 = 3

Which is true so it means all solutions.

Hope this helps.

8 0
3 years ago
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