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pantera1 [17]
4 years ago
14

if an object is thrown directly upwards remains in the air for 5.6s before it returns to its original position, how long did it

take to reach its maximum height?
Physics
2 answers:
Mila [183]4 years ago
6 0
Okay so an object gets thrown upwards so the half way point of the trip would be the maximum height (before it starts coming back down). if the object stays in the air for a total of 5.6s, then that is the time it takes to go up and come back down. to find the time to maximum height, half the time of the whole trip

5.6s/2 = 2.8s
den301095 [7]4 years ago
6 0
Without air resistance there is only gravity pulling on the object. The force of gravity in this case does not change, so the time up should be the same as the time down.
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