Answer:
Acceleration, ![a=1.08\times 10^{13}\ m/s^2](https://tex.z-dn.net/?f=a%3D1.08%5Ctimes%2010%5E%7B13%7D%5C%20m%2Fs%5E2)
Explanation:
It is given that,
Side of the square plate, l = 1 m
Charge on the square plate, ![Q=-2\times 10^{-6}\ C](https://tex.z-dn.net/?f=Q%3D-2%5Ctimes%2010%5E%7B-6%7D%5C%20C)
Position of a proton, x = 1 cm
The electric field due to a parallel plate is given by :
![E=\dfrac{Q}{2A\epsilon_o}](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7BQ%7D%7B2A%5Cepsilon_o%7D)
Electric force is given by :
F = q E
![F=\dfrac{Qe}{2A\epsilon_o}](https://tex.z-dn.net/?f=F%3D%5Cdfrac%7BQe%7D%7B2A%5Cepsilon_o%7D)
e is the charge on electron
The acceleration of the proton can be calculated as :
![a=\dfrac{F}{m}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7BF%7D%7Bm%7D)
m is the mass of proton
![a=\dfrac{Qe}{2A\epsilon_o m}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7BQe%7D%7B2A%5Cepsilon_o%20m%7D)
![a=\dfrac{2\times 10^{-6}\times 1.6\times 10^{-19}}{2(1)^2\times 8.85\times 10^{-12}\times {1.67\times 10^{-27}}}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7B2%5Ctimes%2010%5E%7B-6%7D%5Ctimes%201.6%5Ctimes%2010%5E%7B-19%7D%7D%7B2%281%29%5E2%5Ctimes%208.85%5Ctimes%2010%5E%7B-12%7D%5Ctimes%20%7B1.67%5Ctimes%2010%5E%7B-27%7D%7D%7D)
![a=1.08\times 10^{13}\ m/s^2](https://tex.z-dn.net/?f=a%3D1.08%5Ctimes%2010%5E%7B13%7D%5C%20m%2Fs%5E2)
So, the acceleration of the proton is
. Hence, this is the required solution.
This means it has TWO poles
The 2 poles are NORTH and SOUTH
Hi!
The energy of the block is 4 m/s
To calculate this, you need to use the equation for
kinetic energy. The block is sliding (i.e. it's moving). If the object is sliding across a level surface, the only energy it has is kinetic energy, because
there is no change in potential energy (which changes with height). So, the mechanical energy will be pure kinetic energy. The equation is the following, derived from the expression for kinetic energy:
![v= \sqrt{ \frac{2*Ke}{m}}=\sqrt{ \frac{2*20 (kg*m^{2}*s^{-2}) }{2,5kg}}=4 m/s](https://tex.z-dn.net/?f=v%3D%20%5Csqrt%7B%20%5Cfrac%7B2%2AKe%7D%7Bm%7D%7D%3D%5Csqrt%7B%20%5Cfrac%7B2%2A20%20%28kg%2Am%5E%7B2%7D%2As%5E%7B-2%7D%29%20%7D%7B2%2C5kg%7D%7D%3D4%20m%2Fs)
Have a nice day!
The linear speed of the pepperoni is 0.628 m/s. Its direction is tangential to the circle.
We know that;
v = rω
r = radius of the piece = 10 cm or 0.1 m
ω = angular velocity
We have to convert 60 revolutions per minute to radians per second
1 rev/min = 0.10472 rad/s
60 revolutions per minute = 60 rev/min × 0.10472 rad/s/1 rev/min
= 6.28 rad/s
v = 0.1 m × 6.28 rad/s
v = 0.628 m/s
The direction of this velocity is tangential to the circle.
Learn more: brainly.com/question/4612545