A child walks due east on the deck of a ship at 2 miles per hour. the ship is moving north at a speed of 18 miles per hour. find
the speed and direction of the child relative to the surface of the water.
1 answer:
Refer to the figure shown below.
The velocity of the child and the velocity of the ship should be added vectorially to find the speed and direction of the child relative to the water surface.
The magnitude of the child's velocity is
v = √(2² + 18²) = 18.11 mph
The direction of the child's speed is
θ = tan⁻¹ (18/2) = tan⁻¹ 9 = 83.7° north of east or counterclockwise from the eastern direction.
Answer:
The magnitude is 18.1 mph.
The direction is 84° north of east.
The velocity of the child and the velocity of the ship should be added vectorially to find the speed and direction of the child relative to the water surface.
The magnitude of the child's velocity is
v = √(2² + 18²) = 18.11 mph
The direction of the child's speed is
θ = tan⁻¹ (18/2) = tan⁻¹ 9 = 83.7° north of east or counterclockwise from the eastern direction.
Answer:
The magnitude is 18.1 mph.
The direction is 84° north of east.
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Answer:
The total distance covered by the car is 3,810.08 m
Explanation:
Given;
initial speed of the car, u = 72 km/hr = 20 m/s
initial time, t₁ = 15 minutes = 900 s
final speed of the car, v = 80 km/hr = 22.22 m/s
final time, t₂ = 12 minutes = 720 s
The acceleration of the car is given as;
The total distance covered by the car is given as;
v² = u² + 2as
where;
s is the total distance covered by the car
22.22² = 20² + 2(0.0123)s
22.22² - 20² = 2(0.0123)s
93.728 = 0.0246s
s = 93.728 / 0.0246
s = 3,810.08 m
Therefore, the total distance covered by the car is 3,810.08 m
Explanation:
✠ This question says that there is an object and its mass is 2 kg ; it's raised to a height 10 m and possess potential energy of 200 J. Now this question ask us to find the kinetic energy and the potential energy at a height 4 metre.
✰ Mass = 2 kilograms
✰ Raised height = 10 metres
✰ Posses potential energy = 200 Joules
✰ Kinetic energy at a height 4 metre
✰ Potential energy at a height 4 metre
✰ Kinetic energy at a height 4 metre = 120 J
✰ Potential energy at a height 4 metre = 80 J
✰ Potential energy formula.
✰ Potential energy = mgh
✰ Potential energy as P.E
✰ Mass as m
✰ Joules as J
✰ Height as h
✰ Raised height as g
↦ Potential energy = mgh
↦ Potential energy = 2 × 10 × 4
↦ Potential energy = 20 × 4
↦ Potential energy = 80 J
<h3>✠ Now according to the question let us find the kinetic energy</h3>↦ Kinetic energy = Posses potential energy - Finded potential energy
↦ Kinetic energy = 200 J - 80 J
↦ Kinetic energy = 120 Joules