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3 years ago

Examples of motor and generator?

Physics

2 answers:

Dafna11 [192]3 years ago

6 0

Hope this helps

Answer:In a generator, current is produced in the armature winding. Ceiling fans, cars, etc. are all examples of motor. In power stations, generator is used to generate electricity.

kykrilka [37]3 years ago

6 0

Answer:

In a. generator, current is produced in. the armature winding. Ceiling fans,cars,etc are all examples of motor. In power station, generator is used to generate electricity.

HOPE THIS HELPS

MARK AS BRAINIEST

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svet-max [94.6K]

<h3>Solution:</h3>

Distance (d) = 112 m
Time (t) = 4 seconds
Let the speed be v.
We know, speed = Distance / Time
Therefore, v = d/t

or, v = 112 m ÷ 4 s = 28 m/s

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3 years ago

A car travels 300 km in the first 3 hours of a trip. Then it hits traffic and travels only 60 km during the last hour. What is t

Nadusha1986 [10]

Question

A car travels 300 km in the first 3 hours of a trip. Then it hits traffic and travels only 60 km during the last hour. What is the average speed of the of the car?

300 + 60 = 360 Km (total travel)

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C.) 90 Km/h is your answer

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4 years ago

Water floats on a liquid called "carbon tetrachloride." The two liquids do not mix. A light ray passing from water into carbon t

Oduvanchick [21]

Answer:

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4 years ago

A particle executes simple harmonic motion with an amplitude of 2.00 cm. At what positions does its speed equal one fourth of it

White raven [17]

Answer:

The positions are 0.0194 m and - 0.0194 m.

Explanation:

Given;

amplitude of the simple harmonic motion, A = 2.0 cm = 0.02 m

speed of simple harmonic motion is given as;

$v = \omega \sqrt{A^2-x^2}$

the maximum speed of the simple harmonic motion is given as;

$v_{max} = \omega A$

when the speed equal one fourth of its maximum speed

$v =\frac{v_{max}}{4}$

$\omega\sqrt{A^2-x^2} = \frac{\omega A}{4} \\\\\sqrt{A^2-x^2}= \frac{A}{4}\\\\A^2-x^2 = \frac{A^2}{16} \\\\x^2 = A^2 - \frac{A^2}{16} \\\\x^2 = \frac{16A^2 - A^2}{16} \\\\x^2 = \frac{15A^2}{16} \\\\x= \sqrt{\frac{15A^2}{16} } \\\\x = \sqrt{\frac{15(0.02)^2}{16} }\\\\x = 0.0194 \ m \ \ or\ - 0.0194 \ m$

Thus, the positions are 0.0194 m and - 0.0194 m.

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3 years ago

Q2. EXPLAIN THE CONSTRUCTION AND

Oksi-84 [34.3K]

Answer:

The working of an electric motor is based on the assumption that a conductive current generates a magnetic field around it. Consider the following situation,

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As electricity flows through your simple circuit, you will find that your loop “moves.” The magnet’s magnetic field interferes with that generated by the conductor’s electrical current flow. Because the loop has become a magnet, it will draw one side of it to the magnet’s north pole, and the other to the south pole. That causes the loop to rotate continuously. This is the idea of an electric motor working.

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3 years ago

Examples of motor and generator?​

Examples of motor and generator?