Answer:
you just multiply it
Step-by-step explanation:
x=36
Answer/Step-by-step explanation:
Let x hours be the number of hours Issac worked
x+6 hours be the number of hours Ruby worked
4(x+6) hours be the number of hours Svetlana worked.
x + x + 6 + 4(x+6) = 126
x + x + 6 + 4x +24 = 126
6x +30 = 126
6x = 96
x = 16
Therefore, Issac worked 16 hours.
Ruby worked 16+6 = 22 hours
Svetlana worked 22 × 4 = 88 hours.
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The correct answer is seven
<span>(8.23 x 10^9) (9.1 x 10^9)
(</span>8.23 * 9.1) (10^9 * 10^9)
74.893 * 10^18
7.4893 * 10^19
7.4893 e19
In order to solve this exercise, you have to know the limit that defines the constant
:
![\displaystyle \lim_{n\to\infty} \left(1+\frac{1}{n}\right)^n=e](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Clim_%7Bn%5Cto%5Cinfty%7D%20%5Cleft%281%2B%5Cfrac%7B1%7D%7Bn%7D%5Cright%29%5En%3De)
With this limit in mind, we can perform the following variable change:
![y=\dfrac{1}{x}](https://tex.z-dn.net/?f=y%3D%5Cdfrac%7B1%7D%7Bx%7D)
With this new variable, we have
![x\to 0 \implies \frac{1}{x}=y\to\infty,\quad x = \dfrac{1}{y},\quad \dfrac{1}{x}=y](https://tex.z-dn.net/?f=x%5Cto%200%20%5Cimplies%20%5Cfrac%7B1%7D%7Bx%7D%3Dy%5Cto%5Cinfty%2C%5Cquad%20x%20%3D%20%5Cdfrac%7B1%7D%7By%7D%2C%5Cquad%20%5Cdfrac%7B1%7D%7Bx%7D%3Dy)
Substituting these pieces one by one, we have
![\displaystyle \lim_{x\to 0}\left(1+x\right)^\frac{1}{x} = \lim_{y\to\infty}\left(1+\frac{1}{y}\right)^y](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Clim_%7Bx%5Cto%200%7D%5Cleft%281%2Bx%5Cright%29%5E%5Cfrac%7B1%7D%7Bx%7D%20%3D%20%5Clim_%7By%5Cto%5Cinfty%7D%5Cleft%281%2B%5Cfrac%7B1%7D%7By%7D%5Cright%29%5Ey)
and this is the limit that defines e.