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3 years ago

Which of the following pairs lists a substance that can neutralize HNO, and the salt that would be produced from the reaction?

Chemistry

1 answer:

kolbaska11 [484]3 years ago

5 0

Answer:

To neutralize nitric acid we will need a base which is ammonia.

Explanation:

Neutralization reaction is defined as the chemical reaction in which an acid reacts with a base to produce a salt and water molecule.

The chemical equation for neutralization reaction follows:

$HA+BOH\rightarrow BA(salt)+H_2O$

So, in order to neutralize nitric acid we will need a base which is ammonia.

$NH_3+HNO_3\rightarrow NH_4NO_3$

As we know that ammonia is Bronsted lowry base which can accept proton. So, ammonia will accept the proton given by nitric acid to form ammonium ion.And this ammonium ion formed carries positive charge which combine with nitrate ion to form ammonium nitrate as a product.

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What is the formula for gunpowder

mrs_skeptik [129]

Here is the chemical equation for gun powder, in it’s simple form:

2 KNO3 + S + 3 C → K2S + N2 + 3 CO2.

This is the same simplified formula, only balanced:

10 KNO3 + 3 S + 8 C → 2 K2CO3 + 3 K2SO4 + 6 CO2 + 5 N2.

3 0

3 years ago

A piece of wood has a labeled length value of 63.2 cm. You measure its length three times and record the following data: 63.1 cm

Ulleksa [173]

Percent error (%)= $\frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100$

Accepted value is true value.

Measured values is calculated value.

In the question given Accepted value (true value) = 63.2 cm

Given Measured(calculated values) = 63.1 cm , 63.0 cm , 63.7 cm

1) Percent error (%) for first measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.1 cm

Percent error (%)= $\frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100$

$Percent error = \frac{\left | 63.2 - 63.1 \right |}{63.2}\times 100$

$Percent error = \frac{0.1}{63.2}\times 100$

$Percent error = 0.00158\times 100$

Percent error = 0.158 %

2) Percent error (%) for second measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.0 cm

Percent error (%)= $\frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100$

$Percent error = \frac{\left | 63.2 - 63.0 \right |}{63.2}\times 100$

$Percent error = \frac{0.2}{63.2}\times 100$

$Percent error = 0.00316\times 100$

Percent error = 0.316 %

3) Percent error (%) for third measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.7 cm

Percent error (%)= $\frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100$

$Percent error = \frac{\left | 63.2 - 63.7 \right |}{63.2}\times 100$

$Percent error = \frac{\left | -0.5 \right |}{63.2}\times 100$

$Percent error = \frac{(0.5)}{63.2}\times 100$

$Percent error = 0.00791\times 100$

Percent error = 0.791 %

Percent error for each measurement is :

63.1 cm = 0.158%

63.0 cm = 0.316%

63.7 cm = 0.791%

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