You can download the answer here
C₁ * V₁ = C₂ * V₂
18 * V₁ = 6.0 * 250
18 V₁ = 1500
V₁ = 1500 / 18
V₁ = 83.33 mL
hope this helps!
Answer:
(☞ ಠ_ಠ)☞
Newton's. first law of motion states that "Everybody continues in its state of rest or uniform motion in a straight line unless it is acted by some external forces".
Explanation:
hope it helps
good day
tysm (≧▽≦)
<u>Answer:</u> The pH of the buffer is 4.61
<u>Explanation:</u>
To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:
![pH=pK_a+\log(\frac{[\text{conjuagate base}]}{[\text{acid}]})](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%28%5Cfrac%7B%5B%5Ctext%7Bconjuagate%20base%7D%5D%7D%7B%5B%5Ctext%7Bacid%7D%5D%7D%29)
We are given:
= negative logarithm of acid dissociation constant of weak acid = 4.70
![[\text{conjuagate base}]}](https://tex.z-dn.net/?f=%5B%5Ctext%7Bconjuagate%20base%7D%5D%7D)
= moles of conjugate base = 3.25 moles
![[\text{acid}]](https://tex.z-dn.net/?f=%5B%5Ctext%7Bacid%7D%5D)
= Moles of acid = 4.00 moles
pH = ?
Putting values in above equation, we get:
Hence, the pH of the buffer is 4.61
