All categories

4 years ago

Which of the following does not involve colligative properties?

2 answers:

fomenos4 years ago

7 0

Colligative properties are usually used in relation to solutions.
Colligative properties are those properties of solutions, which depend on the concentration of the solutes [molecules, ions, etc.] in the solutions and not on the chemical nature of those chemical species. Examples of colligative properties include: vapour pressure depression, boiling point elevation, osmotic pressure, freezing point depression, etc.
For the question given above, the correct option is D. This is because the statement is talking about freezing point elevation, which is not part of colligative properties.

vodka [1.7K]4 years ago

3 0

Hey there!

The correct answer to your question is:

Option D)
Calcium silicide is added to liquid steel to increase the steel’s ability to freeze.

Hope this helps!
Have a great day (:

You might be interested in

How many liters of water vapor can be produced if 8.9 liters of methane gas (CH4) are combusted, if all measurements are taken a

Burka [1]

From the chemical equation given, one mole of CH4 yields two moles of water (H2O). If all the methane gas that is 8.9 L is combusted then the volume of water produced is the number of moles H2O times the volume of the methane gas used up, that is 8.9 L × 2 = 17.8 L of water produced.

5 0

3 years ago

A region of metamorphic rock lies far beneath Earth’s surface. In time, which two ways can the rock make its way upward to Earth

NeX [460]

It can uplift slowly due to the pressure of Earth’s plates.

It can melt into magma and recrystallize as extrusive igneous rock.

8 0

4 years ago

Read 2 more answers

An ideal gas in a cylindrical container of radius r and height h is kept at constant pressure p. The bottom of the container is

Juli2301 [7.4K]

Answer:

$m =\frac{p*(pi)*r^{2}*h*mw}{R*\frac{T_{1} + T_{O}}{2}}$

Explanation:

The gas ideal law is

PV= nRT (equation 1)

Where:

P = pressure

R = gas constant

T = temperature

n= moles of substance

V = volume

Working with equation 1 we can get

$n =\frac{PV}{RT}$

The number of moles is mass (m) / molecular weight (mw). Replacing this value in the equation we get.

$\frac{m}{mw} =\frac{PV}{RT}$ or

$m =\frac{P*V*mw}{R*T}$ (equation 2)

The cylindrical container has a constant pressure p

The volume is the volume of a cylinder this is

$V =(pi)*r^{2}*h$

Where:

r = radius

h = height

(pi) = number pi (3.1415)

This cylinder has a radius, r and height, h so the volume is $V =(pi)*r^{2}*h$

Since the temperatures has linear distribution, we can say that the temperature in the cylinder is the average between the temperature in the top and in the bottom of the cylinder. This is:

$T =\frac{T_{1} + T_{O}}{2}$

Replacing these values in the equation 2 we get:

$m =\frac{P*V*mw}{R*T}$ (equation 2)

$m =\frac{p*(pi)*r^{2}*h*mw}{R*\frac{T_{1} + T_{O}}{2}}$

8 0

4 years ago

Which compound has the highest melting point? Al2(CO3)3 C12H22O11 C8H18 H2O

Rasek [7]

Answer:

Al2(CO3)3 (A)

Explanation:

i think thats the answer

6 0

3 years ago

Read 2 more answers

Help me with my work please thanks?!

masya89 [10]

Answer:

lighting a match or water and salt

5 0

3 years ago