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3 years ago

A triangle has sides that measures 9 inches and 17 inches.what is the possible length of the third side

Mathematics

1 answer:

Marrrta [24]3 years ago

4 0

Answer:

Step-by-step explanation:

Its known that the sum of 2 sides should be greater than the third, therefore,

Let the third side be x,

9+17=26 (x is smaller than 26 but greater than 17)

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PLEASEE HELP!!

Alex777 [14]

Answer:

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>

quadratic equation
quadratic equation word problems
solving quadratic

<h3>given:</h3>

h(t) = -4t² + 12t + 100

<h3>to solve:</h3>

<h3>tips and formulas:</h3>

<u>the</u><u> </u><u>Ball</u><u> </u><u>will</u><u> </u><u>hit </u><u>the</u><u> ground</u><u> </u><u>when</u><u> </u><u>the</u><u> height</u><u> is</u><u> </u><u>0</u>
<u>solving</u><u> </u><u>quadratics </u><u>using</u><u> </u><u>quadratic</u><u> formula</u>
<u>PEMDAS</u>

<h3>let's solve: </h3>

$step - 1 : \: define$

$- 4 {t}^{2} + 12t + 100 = 0$

$step - 2 : \\ divide \: both \: sides \: by \: - 4$

${t}^{2} - 3t - 25 = 0$

$step - 3 : \\ solve \: the \: quadratic$

$formula : \\ x = \frac{ - b± \sqrt{ {b}^{2} - 4ac } }{2a}$

$define \: a ,b \: and \: c \\ which \: are \: 1, - 3 \: and \: - 25 \: respectively$

$t = \frac{ - ( - 3)± \sqrt{ {( - 3)}^{2} - 4.1. - 25 } }{2.1}$

$t = \frac{ 3± \sqrt{ 9 + 100} }{2}$

$t = \frac{3 + \sqrt{ 109 } }{2}$

$t = \frac{3 - \sqrt{ 109 } }{2}$

$t = 6.7 \\ t = - 3.7$

$as \: we \: know \: time \: cannot \: be \: negative$

$\huge \therefore \: t = 6.7$

5 0

3 years ago

What decimal represent 1/8?

jenyasd209 [6]

1/8 is equivalent to 0.125. I hope this helps!

6 0

4 years ago

The formula for the area of a triangle is A = {bn, where b is the length of the base and h is the height.

yan [13]

Answer:

5 units

Step-by-step explanation:

Area of triangle = 1/2 × base × height

30 = 1/2 × 12 × height

Height = 30 × 2/12 = 5 units

3 0

3 years ago

Read 2 more answers

The triangles below are similar. Triangle A B C. Side A C is 10 and side A B is 5. Angle C is 30 degrees. Triangle D E F. Side E

Gnoma [55]

Answer:

$\triangle ABC {\displaystyle \sim } \triangle DE\ F$

$\triangle CBA {\displaystyle \sim } \triangle FED$

$\triangle BAC {\displaystyle \sim } \triangle EDF$

Step-by-step explanation:

Given

$\triangle ABC {\displaystyle \sim } \triangle DE\ F$

$AC = 10$

$AB = 5$

$\angle C = 30^\circ$

$ED = 7.5$

$DF = 25$

$\angle F =30$

$\angle E =90$

Required

Which of the options is/are true:

$\triangle CBA {\displaystyle \sim } \triangle FED$ $\triangle CBA {\displaystyle \sim } \triangle FDE$ $\triangle BAC {\displaystyle \sim } \triangle EFD$

$\triangle BAC {\displaystyle \sim } \triangle EDF$ $\triangle ABC {\displaystyle \sim } \triangle DE\ F$ $\triangle ABC {\displaystyle \sim } \triangle DFE$

The given triangles, implies that:

$A {\displaystyle \sim } \ D$

$B {\displaystyle \sim } \ E$

$C {\displaystyle \sim } \ F$

By taking each sides of both triangle, one after the other; the possible similar triangles are:

$\triangle ABC {\displaystyle \sim } \triangle DE\ F$

$\triangle CBA {\displaystyle \sim } \triangle FED$

$\triangle BAC {\displaystyle \sim } \triangle EDF$

5 0

3 years ago

Si un rombo tiene un lado con medida de 16 pulgadas. Cual es su perimetro . If a rhombus has a side measured 16 inches. What is

kap26 [50]

Answer:

64 inches or 64 pulgadas

Step-by-step explanation:

The formula for the perimeter of a rhombus is given as:

P = 4a

Where a = side length of the rhombus

From the above question, side length of the rhombus = 16 inches

Hence, Perimeter of the rhombus = 4 × 16 inches

= 64 inches

La fórmula para el perímetro de un rombo se da como:

P = 4a

Donde a = longitud del lado del rombo

De la pregunta anterior, la longitud del lado del rombo = 16 pulgadas

Por lo tanto, perímetro del rombo = 4 × 16 pulgadas

= 64 pulgadas

6 0

3 years ago