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artcher [175]
3 years ago
6

Two ants start at the origin of the rectangular grid shown above where each unit represents an inch. They roam around in differe

nt directions for exactly 30 seconds. Ant A ends at point (-3,5) while Ant B ends at points (4,-2). How far apart are the two ants at the end of 30 seconds?
Mathematics
1 answer:
weeeeeb [17]3 years ago
3 0
To help clarify the problem, we can plot the two ants on a graph (see attached image). However, we don't need the graph to solve the problem.

Let's first find the distance in their 'x' values:
= |-3| + |4|
The '| |' means that we don't care if it is negative, we just want the positive value.
= |-3| + |4| is the same thing as = 3 + 4
= 7

Now let's find the distance in their 'y' values:
= |5| + |-2|
= 7

From here, since we have the 'x' and 'y' distances, we can create a triangle. The 'x' and 'y' will be our side lengths, and the hypotenuse is then the distance between the two ants. 

In order to find the hypotenuse, we use the Pythagorean theorm: c^{2}=a^{2}+b^{2}

Now we plug and solve:
c^{2}=(7)^{2} + (7)^{2}
c^{2}=98
c= \sqrt{98}

∴The distance between the two ants is \sqrt{98} or 9.899

Hope this helps!


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Answer:

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Step-by-step explanation:

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Distance travelled in one hour:

\begin{aligned}v \cdot t &= 13.2 \; \rm m \cdot s^{-1} \times 3600\; \rm s \\ &= 47520\; \rm m\end{aligned}.

Number of revolutions required for covering that distance:

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Harman [31]
1/3 or 5/6 

Lets make the fractions into decimals. To make a fraction into decimal you have to divide the numerator by the denominator. The numerator is the top part of a fraction and the denominator is the bottom part of the fraction. 

≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡

Calculations

1/3
1 ÷ 3 =  0.3333.... 

5/6 
5 ÷ 6 = 0.83333...

0.83333... is greater then 0.3333.....
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Answer:

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61 - 30 is 31.

The missing number is 31/100. See image.

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jolli1 [7]

Answer:

Step-by-step explanation:

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Slope = 2

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2 years ago
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