3 9
_ * _
15 6
Compare diagonally to see if they the 2 numbers simplify.
Ex:
3 and 6 Simplify to 1 and 2 because they are both multiples of 3.
9 and 15 Simplify to 3 and 5 because they are both multiples of 3 as well.
Now our fractions are
1 3
_ * _
5 2
Now multiply across to get your final fraction/answer
3
_
10
Answer:
The
term of the given sequence

Step-by-step explanation:
<u>Step(i):-</u>
Given sequence 2 , 5, 
First term a = 2
The difference of given geometric sequence

<u><em>Step(ii):-</em></u>
The
term of the given sequence

The
term of the given sequence


The minimum distance is the perpendicular distance. So establish the distance from the origin to the line using the distance formula.
The distance here is: <span><span>d2</span>=(x−0<span>)^2</span>+(y−0<span>)^2
</span> =<span>x^2</span>+<span>y^2
</span></span>
To minimize this function d^2 subject to the constraint, <span>2x+y−10=0
</span>If we substitute, the y-values the distance function can take will be related to the x-values by the line:<span>y=10−2x
</span>You can substitute this in for y in the distance function and take the derivative:
<span>d=sqrt [<span><span><span>x2</span>+(10−2x<span>)^2]
</span></span></span></span>
d′=1/2 (5x2−40x+100)^(−1/2) (10x−40)<span>
</span>Setting the derivative to zero to find optimal x,
<span><span>d′</span>=0→10x−40=0→x=4
</span>
This will be the x-value on the line such that the distance between the origin and line will be EITHER a maximum or minimum (technically, it should be checked afterward).
For x = 4, the corresponding y-value is found from the equation of the line (since we need the corresponding y-value on the line for this x-value).
Then y = 10 - 2(4) = 2.
So the point, P, is (4,2).