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3 years ago

2. Write an equation in slope intercept form with the given Information Goes through points (1, 8) and (5, 0)

Mathematics

1 answer:

pantera1 [17]3 years ago

8 0

Answer:

$y = -2x + 10$

Step-by-step explanation:

Slope: $m = \frac{y_{2}-y_{1} }{x_{2}-x_{1}}$

Slope-Intercept Form: $y=mx+b$

$m=\frac{8-0}{1-5}$

$m = -2$

$y = -2x + b$

$0 = -2 (5)+b$

$0=(-10)+b$

$b = 10$

$y = -2x + 10$

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Pavlova-9 [17]

Step-by-step explanation:

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3 years ago

Please help ASAP! Thanks! For the figures below, assume they are made of semicircles, quarter circles and squares. For each shap

bazaltina [42]

Answer:

Part 1) $A=36(\pi-2)\ cm^2$

Part 2) $P=6(\pi+2\sqrt{2})\ cm$

Step-by-step explanation:

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

$A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)$

we have that the base and the height of triangle is equal to the radius of the circle

$r=12\ cm\\b=12\ cm\\h=12\ cm$

substitute

$A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)$

$A=(36\pi-72)\ cm^2$

simplify

Factor 36

$A=36(\pi-2)\ cm^2$

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

The circumference of a quarter of circle is equal to

$C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r$

substitute the given values

$C=\frac{1}{2}\pi (12)$

$C=6\pi\ cm$

The hypotenuse of right triangle is equal to (applying the Pythagorean Theorem)

$AC=\sqrt{12^2+12^2}$

$AC=\sqrt{288}\ cm$

simplify

$AC=12\sqrt{2}\ cm$

Find the perimeter

$P=(6\pi+12\sqrt{2})\ cm$

simplify

Factor 6

$P=6(\pi+2\sqrt{2})\ cm$

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3 years ago

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2 years ago

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tangare [24]

The next time this will happen again is when its turn 11:11

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4 years ago

NO LINKS!!! Fill in the blanks of this sheet. Part 1

fredd [130]

Problem 1

Answer:

The square root of the expression of the difference of x^2 and 11.
The quotient of 2 times a number and -1
The sum of the square root of two times a number and 11.

------------

Explanation:

The term "difference" is the result of subtraction. We're subtracting the x^2 and 11. Then applying the square root to the result.

Question 2 has the blanks filled correctly.

For the last sentence, we have a sum of the terms $\sqrt{2x}$ and 11.

===========================================================

Problem 2

Answer:

The value of an algebraic expression depends on its variables

Substitute the known value for each variable.
Simplify using the order of operations
Use the work to answer any word problems related to the expression.

------------

Explanation:

The variables are placeholders for numbers

So for instance, saying x+5 is like saying "some unknown number plus 5".

We could replace it with something like x = 10 to get x+5 = 10+5 = 15

Once the variable is replaced, you use the order of operations PEMDAS (some books refer to it as BODMAS).

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2 years ago