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marin [14]
3 years ago
7

Suppose y = 2x + 1 , where x and y are functions of t. (a) if dx/dt = 6, find dy/dt when x = 4. dy dt = (b) if dy/dt = 2, find d

x/dt when x = 24. dx dt =
Mathematics
1 answer:
evablogger [386]3 years ago
7 0

y=2x+1\\\\\dfrac{dy}{dt}=2\dfrac{dx}{dt}

(a) For dx/dt=6, dy/dt = 2·6 = 12

(b) For dy/dt=2, 2 = 2·dx/dt ⇒ dx/dt = 1

_____

The value of x is irrelevant for this question.

=====

If your function is 2^x +1 or 2^(x +1), it needs to be written as such. The answer above applies to the function given.

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12\frac{1}{3} inches

Step-by-step explanation:

So to go from 300 to 3700 you have to multiply by 12\frac{1}{3}

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F(x) = 7x + 9, g(x) = 4x - 1;<br> Find (fºg)(x).
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3 years ago
What is the greatest integer that is less than √6 + √7
lutik1710 [3]

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5

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4 0
3 years ago
I am in need of some help :(It looks so simple yet I don't get how to do it. Can anyone help explain?(picture of question attach
Firdavs [7]

x = 14

Explanation:

height = x

base 1 = 98

base 2 = 2

Using altitude formula in geometric mean:

base 1/height = height/base 2

98/x = x/2

\begin{gathered} \frac{98}{x}=\frac{x}{2} \\ \text{cross multiply:} \\ 2(98)\text{ = x}\times x \end{gathered}\begin{gathered} 196=x^2 \\ \text{square root both sides:} \\ \sqrt[]{196}\text{ = }\sqrt[]{x^2} \\ x\text{ = }\sqrt[]{196} \\ x\text{ = 14} \end{gathered}

5 0
1 year ago
Una diseñadora de modas que confecciona trajes de noche, tarda 3 horas en cortar y 2 horas en coser cada vestido de fiesta. Para
ella [17]

For this case we define the following variables:

x: Number of party dresses

y: Number of suits

You have 30 hours per week to cut, that is, the first equation is given by:

3x + 3y = 30\\

It is also known that 25 hours per week are available for sewing, that is:

2x + 3y = 25\\

It has a system of two equations with two unknowns, solving we have:

3x + 3y = 30\\\\2x + 3y = 25\\

Multiplying the second equation by -1:

3x + 3y = 30\\\\-2x-3y = -25\\

Adding up:

x + 0 = 5\\\\x = 5\\

Substituting x in the first equation:

3 * 5 + 3y = 30\\\\15 + 3y = 30\\

Clearing and:

3y = 30-15\\\\3y = 15\\

y = \frac{15}{3}\\\\y = 5\\

Thus, per week, the designer can produce 5 party dresses and 5 suits working at her maximum capacity.

Answer:

5 Party dresses

5 Suits


5 0
3 years ago
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