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DerKrebs [107]
3 years ago
8

Describe an infinite geometric series with the beginning value of 2 that converges to 10 what are the first four terms of the se

ries
Mathematics
1 answer:
damaskus [11]3 years ago
4 0

Answer:

  • an = 2·(4/5)^(n-1)
  • 2, 8/5, 32/25, 128/125

Step-by-step explanation:

The sum of an infinite geometric series is ...

  S = a1/(1 -r)

where r is the common ratio. The sum will only exist if |r| < 1.

The problem statement tells us S = 10 and a1 = 2, so we have ...

  10 = 2/(1 -r)

  r = 1 -2/10 = 4/5

So the n-th term of the series is ...

  an = a1·r^(n-1)

  an = 2·(4/5)^(n-1)

For values of n = 1 to 4, the terms are ...

  2, 8/5, 32/25, 128/125

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Answer:

Part A = $180

Part B = $104

Step-by-step explanation:

Part A:

You do 255÷5=51

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Part B:

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x = 26


Because 26-2=24 which would be right because it needs to equal the same size as the other side that is across from it.


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1 year ago
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Answer:

I believe its 4.8, which is confusing seeing as its not an option.

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

To the pre-image after a 270°-counterclockwise rotation [90°-clockwise rotation], just reverse it by doing a 270°-clockwise rotation [90°-counterclockwise rotation]:

Extended Rotation Rules

  • 270°-clockwise rotation [90°-counterclockwise rotation] >> (x, y) → (-y, x)
  • 270°-counterclockwise rotation [90°-clockwise rotation] >> (x, y) → (y, -x)
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So, perform your rotation:

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→ <em>B'</em>[-2, 1] was originally at <em>B</em>[-1, -2]

→ <em>A</em><em>'</em>[6, 3] was originally at <em>A</em>[-3, 6]

I am joyous to assist you anytime.

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