1) the types of number are the negative integers (e.g √-1 √-3 <span>√-5 are not defined)
2) the answer is No, proof: 2x</span>√-1 is not defined because <span>√-1 doesn't exist
3) the answer is No, proof: </span>√-1 - 3 is not defined because √-1 doesn't exist
4) the answer is Yes, proof: (√-1 )²= -1 this is a real number
5) the answer is No, proof: (√-1 )^3= (√-1 )²(√-1 )= - 1(√-1 ), and - 1(√-1 ) is not defined because √-1 doesn't exist
6) the result would be defined with the following cases:
√-1+n, n>1
√-1xn, n<0
√-1/n, n<0
7) the result would not be defined with the following cases:
√-1+n, n<0
√-1xn, n>0
√-1/n, n>0
8) to square <span>3 + √-1, I use the method of complex number
i²= -1, it implies i= </span>√-1
so 3+√-1=3+i, and then (3+√-1)²=(3+i)²= 9 -1+6i= 8-i= 8-√-1
9) it is used for finding complex roots of a number
Simplify. Note the equal sign. What you do to one side, you do to the other. Follow PEMDAS.
Isolate the x.
First, distribute 6 to all terms within the parenthesis
6(-3) = -18
6(4x) = 24x
7x - 18 + 24x = 199
Simplify. Combine like terms
31x - 18 = 199
Isolate the x. Add 18 to both sides
31x - 18 (+18) = 199 (+18)
31x = 199 + 18
31x = 217
Isolate the x. Divide 31 from both sides
31x/31 = 217/31
x = 217/31
x = 7
7 is your answer for x
hope this helps
Answer:
i dont under stand sorry i cant help sorry
