A roller coaster moves 200 ft horizontally, then rises 135 ft at an angle of 30.0° above the horizontal. Next, it travels 135 f
t at an angle of 40.0° below the horizontal. Use graphical techniques to find the roller coaster's displacement from its starting point at the end of this movement.
1 answer:
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Answer:
The thrown rock strike 2.42 seconds earlier.
Explanation:
This is an uniformly accelerated motion problem, so in order to find the arrival time we will use the following formula:
So now we have an equation and unkown value.
for the thrown rock
for the dropped rock
solving both equation with the quadratic formula:
we have:
the thrown rock arrives on t=5.4 sec
the dropped rock arrives on t=7.82 sec
so the thrown rock arrives 2.42 seconds earlier (7.82-5.4=2.42)