A roller coaster moves 200 ft horizontally, then rises 135 ft at an angle of 30.0° above the horizontal. Next, it travels 135 f
t at an angle of 40.0° below the horizontal. Use graphical techniques to find the roller coaster's displacement from its starting point at the end of this movement.
1 answer:
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When an object gets heated by a temperature ΔT energy needed, E = mcΔT
Here energy is given E = 2050 J
Mass of object = 150 g
Change in temperature ΔT = 15 = 15 K
a) Heat capacity of an object equal to the ratio of the heat added to (or removed from) an object to the resulting temperature change.
So heat capacity = E/ΔT = 2050/15 = 136.67 J/K
b) We have E = mcΔT
c =
So object's specific heat = 911.11 J/kgK
Answer:
0.652 mA
Explanation:
According to Faraday's Law :
where ;
A =
Induced current I =
=
=
= 0.652 mA
Thus, the induced current in the loop of wire over this time = 0.652 A