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Contact [7]
4 years ago
5

The formula for the area of a circle is A= ar?m where A is the area and r is the radius. The subject of

Mathematics
2 answers:
DanielleElmas [232]4 years ago
8 0

Answer:

r = \sqrt{ \frac{A}{ \pi}}

Step-by-step explanation:

A =\pi r^2 \\Divide\: both \:sides\:of\:the\:equation \\\frac{A}{ \pi} =\frac{ \pi r^2}{ \pi} \\r^2 = \frac{A}{ \pi} \\\sqrt{r^2} =\sqrt{ \frac{A}{ \pi}} \\\\r = \sqrt{ \frac{A}{ \pi}}

Bad White [126]4 years ago
6 0

Hi there! :)

Answer:

\sqrt{\frac{A}{\pi } } = r

Step-by-step explanation:

Formula for the area of a circle:

A = \pi r^{2}

Rearrange the equation in terms of "r":

Divide 'π' from both sides:

\frac{A}{\pi }  = r^{2}

Take the square root of both sides:

\sqrt{\frac{A}{\pi } } = r

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Suppose D is the event that a given patient has the disease, and P is the event of a positive test result.

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\mathbb P(D)=0.01
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\mathbb P(P^C)=\mathbb P(P^C\cap D)+\mathbb P(P^C\cap D^C)

That is, in order for P^C to occur, it must be the case that either D also occurs, or D^C does. Then from the definition of conditional probability we expand this as

\mathbb P(P^C)=\mathbb P(D)\mathbb P(P^C\mid D)+\mathbb P(D^C)\mathbb P(P^C\mid D^C)

so we get

\mathbb P(P^C)=0.01\cdot0.02+0.99\cdot0.95=0.9407

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By the definition of conditional probability,

\mathbb P(D\mid P)=\dfrac{\mathbb P(D\cap P)}{\mathbb P(P)}

We have the probabilities of P/P^C occurring given that D/D^C occurs, but not vice versa. However, we can expand the probability in the numerator to get a probability in terms of P being conditioned on D:

\mathbb P(D\cap P)=\mathbb P(D)\mathbb P(P\mid D)

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\mathbb P(P)=\mathbb P(P\cap D)+\mathbb P(P\cap D^C)

or in terms of conditional probabilities,

\mathbb P(P)=\mathbb P(D)\mathbb P(P\mid D)+\mathbb P(D^C)\mathbb P(P\mid D^C)

so that

\mathbb P(D\mid P)=\dfrac{\mathbb P(D)\mathbb P(P\mid D)}{\mathbb P(D)\mathbb P(P\mid D)+\mathbb P(D^C)\mathbb P(P\mid D^C)}

which is exactly what Bayes' rule states. So we get

\mathbb P(D\mid P)=\dfrac{0.01\cdot0.98}{0.01\cdot0.98+0.99\cdot0.05}\approx0.1653
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