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3 years ago

Q4 Q20.) Give the equation of the exponential function whose graph is shown.

Mathematics

1 answer:

Elodia [21]3 years ago

3 0

Hi again!

I used an online calculator to help me graph each of the functions.

The correct answer is option D

Let me know if you have any questions about the answer!

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Collin states that 8+(16+9)=(8+16)+9 is always true . Which of the following properties would prove Collin is correct? 1# transi

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3. associative property of addition.

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3 years ago

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Which of the following equations is correct? select three that apply

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Answer:b,e,f

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3 years ago

Find the value of x in the triangle shown below

beks73 [17]

Answer:

x = 12

Step-by-step explanation:

Using the Pythagorean theorem where c = 13, and b = 5, we get (a = x):

$a^2 + 5^2 = 13^2$

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$a^2 = 13^2-5^2$

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3 years ago

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Name a parallelogram that is neither a square, rhombus nor rectangle

Vedmedyk [2.9K]

With all due thinking...

I think a Diamond shape will befit your answer. So; The real answer is "Rhomboid"

The reason is that...

A rhomboid has four parallel sides. The opposite sides are equal, but the corners do not form right angles. Think of a rectangle that is slanted(a.k.a diamond) Thats what a Rhomboid is...

A parallelogram that dosent have equal sides is not a rhombus; and which dosent have Right angles are not rectangles and hence cannot be aquares either.

So in all Way a Rhomboid will mark the answer for your question.

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4 years ago

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<img src="https://tex.z-dn.net/?f=%5Cfrac%7B3x%5E%7B8%7D%2A7x%5E%7B3%7D%20%7D%7B3x%5E%7B6%7D%2A7%20%7D" id="TexFormula1" title="

denis23 [38]

Answer:

$a = \dfrac{x^2}{3} \quad \textsf{and} \quad b = \dfrac{x^3}{7}$

Step-by-step explanation:

Given expression:

$\dfrac{3x^{8} \cdot 7x^{3} }{3x^{6} \cdot 7 }$

There are several ways this problem can be approached, and therefore many different answers. The goal is to reduce the given expression to a simple product of two terms in x, set that to the given form 3a⋅7b then solve for a and b.

$\implies \dfrac{3x^{8} \cdot 7x^{3} }{3x^{6} \cdot 7}$

Cancel the common factors 3 and 7:

$\implies \dfrac{\diagup\!\!\!\!3x^{8} \cdot \diagup\!\!\!\!7x^{3} }{\diagup\!\!\!\!3x^{6} \cdot \diagup\!\!\!\!7}$

$\implies \dfrac{x^8 \cdot x^3}{x^6}$

Separate the fraction:

$\implies \dfrac{x^8}{x^6} \cdot x^3$

$\textsf{Apply the quotient rule of exponents} \quad \dfrac{a^b}{a^c}=a^{b-c}:$

$\implies x^{8-6} \cdot x^3$

$\implies x^{2} \cdot x^3$

Now equate the simplified expression to the given form:

$\implies x^{2} \cdot x^3=3a \cdot 7b$

Therefore:

$\begin{aligned}x^{2} &=3a \:\: &\textsf{ and }\:\: \quad x^3 &=7b\\ \Rightarrow a & = \dfrac{x^2}{3} & \Rightarrow b & = \dfrac{x^3}{7}\end{aligned}$

However, we could also separate them as:

$\begin{aligned}x^{3} &=3a \:\: &\textsf{ and }\:\: \quad x^2 &=7b\\ \Rightarrow a & = \dfrac{x^3}{3} & \Rightarrow b & = \dfrac{x^2}{7}\end{aligned}$

Another way of writing them would be to go back a few steps and separate the fraction in x terms differently:

$\implies \dfrac{x^8 \cdot x^3}{x^6}=x^8 \cdot \dfrac{x^3}{x^6}=x^8 \cdot x^{-3}$

Therefore, this would give us:

$\begin{aligned}x^{8} &=3a \:\: &\textsf{ and }\:\: \quad x^{-3} &=7b\\ \Rightarrow a & = \dfrac{x^8}{3} & \Rightarrow b & = \dfrac{1}{7x^3}\end{aligned}$

As the given expression reduces to x⁵, we can separate the x term in any way we like, so long as the coefficient of a is ¹/₃ and the coefficient of b is ¹/₇. Therefore, there are many possible answers.

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2 years ago

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