Answer:
410.4J
Explanation:
Step one:
given
mass= 3.35kg
weight= 3.35*9.81= 32.86N
h=12.49m
Required
The net work done
Step two:
the work done is given as
WD= force* distance
WD= 32.86*12.49
WD= 410.4J
Answer:
![P = 1.09 \times 10^8 Pa](https://tex.z-dn.net/?f=P%20%3D%201.09%20%5Ctimes%2010%5E8%20Pa)
Explanation:
As we know that the pressure inside the liquid level is given as
![P = \rho g h + P_o](https://tex.z-dn.net/?f=P%20%3D%20%5Crho%20g%20h%20%2B%20P_o)
here we have
![\rho = 1024 kg/m^3](https://tex.z-dn.net/?f=%5Crho%20%3D%201024%20kg%2Fm%5E3)
h = 10.9 km
also we know that
![P_o = 1.01 \times 10^5 Pa](https://tex.z-dn.net/?f=P_o%20%3D%201.01%20%5Ctimes%2010%5E5%20Pa)
now we have
![P = (1.01 \times 10^5) + (1024)(9.81)(10.9 \times 10^3)](https://tex.z-dn.net/?f=P%20%3D%20%281.01%20%5Ctimes%2010%5E5%29%20%2B%20%281024%29%289.81%29%2810.9%20%5Ctimes%2010%5E3%29)
![P = 1.09 \times 10^8 Pa](https://tex.z-dn.net/?f=P%20%3D%201.09%20%5Ctimes%2010%5E8%20Pa)
To solve this problem, we are going to use the formula for
work which is Fd where x and y are measured separately.
X direction: W = 13.5 x 230 = 3105 Joules
Y direction: W = -14.3 x -165 = 2360 Joules
So the total work is getting the sum of the two: 3105 + 2360
= 5465 Joules
Divergent plate limits
These plates can be said to be disparate staying away from the nearest plate with respect to area. This usually above the rising waters of the ocean waters . The rising current moves up on the base of the lithosphere, lifting it and streaming horizontally underneath it