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Irina-Kira [14]
3 years ago
15

H-2 + H-3 → He-4 +

Physics
2 answers:
Svetach [21]3 years ago
6 0
D)
<span>No. the products include He-4, one neutron, and energy.</span>
zhannawk [14.2K]3 years ago
4 0

Answer: Option (D) is the correct answer.

Explanation:

The given reaction is a nuclear fusion reaction because in a nuclear fusion two small nuclei combine together to result in the formation of a large nuclei along with the release of energy.

The complete given reaction will be as follows.

     ^{2}_{1}H + ^{3}_{1}H \rightarrow ^{4}_{2}He + ^{1}_{0}n + Energy

Thus, we can conclude that along with the release of helium atom there will be release of one neutron and energy.

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Complete question:

At a particular instant, an electron is located at point (P) in a region of space with a uniform magnetic field that is directed vertically and has a magnitude of 3.47 mT. The electron's velocity at that instant is purely horizontal with a magnitude of 2×10​⁵​​ m/s then how long will it take for the particle to pass through point (P) again? Give your answer in nanoseconds.

[<em>Assume that this experiment takes place in deep space so that the effect of gravity is negligible.</em>]

Answer:

The time it will take the particle to pass through point (P) again is 1.639 ns.

Explanation:

F = qvB

Also;

F = \frac{MV}{t}

solving this two equations together;

\frac{MV}{t} = qVB\\\\t = \frac{MV}{qVB} = \frac{M}{qB}

where;

m is the mass of electron = 9.11 x 10⁻³¹ kg

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B is the strength of the magnetic field = 3.47 x 10⁻³ T

substitute these values and solve for t

t = \frac{M}{qB} = \frac{9.11 *10^{-31}}{1.602*10^{-19}*3.47*10^{-3}} = 1.639 *10^{-9}  \ s \ = 1.639 \ ns

Therefore, the time it will take the particle to pass through point (P) again is 1.639 ns.

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Hi
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Energy is released during the fission of pu-239 atoms as a result of the
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<h2>Answer: process of converting matter into energy</h2><h2></h2>

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