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Irina-Kira [14]
3 years ago
15

H-2 + H-3 → He-4 +

Physics
2 answers:
Svetach [21]3 years ago
6 0
D)
<span>No. the products include He-4, one neutron, and energy.</span>
zhannawk [14.2K]3 years ago
4 0

Answer: Option (D) is the correct answer.

Explanation:

The given reaction is a nuclear fusion reaction because in a nuclear fusion two small nuclei combine together to result in the formation of a large nuclei along with the release of energy.

The complete given reaction will be as follows.

     ^{2}_{1}H + ^{3}_{1}H \rightarrow ^{4}_{2}He + ^{1}_{0}n + Energy

Thus, we can conclude that along with the release of helium atom there will be release of one neutron and energy.

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An elastic collision is one in which:
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Answer:

.conserves kinetic energy and momentum

.does not coalesce

.causes much lesser deformation as compared to inelastic

.the two bodies involved; after collision move with separate final velocities.

Explanation:

eg. throwing a ball at a wall

<em>collision</em><em> </em><em>between</em><em> </em><em>a</em><em> </em><em>punch</em><em> </em><em>and</em><em> </em><em>your</em><em> </em><em>nose</em><em>,</em><em>haha</em>

<em>I</em><em> </em><em>guess</em><em> </em><em>that</em><em> </em><em>will</em><em> </em><em>cause</em><em> </em><em>a lot</em><em> </em><em>deformation</em><em>.</em><em>.</em>

<em>.</em>

7 0
3 years ago
Plz plz plz plz plz plz hlep me
Amanda [17]

Answer:

decantation, distilling, freezing

6 0
3 years ago
What affects fuel consumption in automobiles?
maksim [4K]

Answer:

A and C

Explanation:

drag (the area of lower air pressure behind the car when moving) and mostly air resistance (the work to push the air in front of us away to move through - the faster we go, the stronger the air resists to move aside).

4 0
2 years ago
A 16-kg sled is being pulled along the horizontal snow-covered ground by a horizontal force of 24 n. starting from rest, the sle
harina [27]
The abweens is 20 because yes
7 0
3 years ago
1. A hydraulic lift is to be used to lift a truck masses 5000 kg. If the diameter of the
zheka24 [161]

Answer:

a)   F = 4.9 10⁴ N,  b)   F₁ = 122.5 N

Explanation:

To solve this problem we use that the pressure is transmitted throughout the entire fluid, being the same for the same height

1) pressure is defined by the relation

           P = F / A

to lift the weight of the truck the force of the piston must be equal to the weight of the truck

          ∑F = 0

          F-W = 0

          F = W = mg

          F = 5000 9.8

          F = 4.9 10⁴ N

the area of ​​the pisto is

          A = pi r²

          A = pi d² / 4

          A = pi 1 ^ 2/4

          A = 0.7854 m²

pressure is

          P = 4.9 104 / 0.7854

          P = 3.85 104 Pa

2) Let's find a point with the same height on the two pistons, the pressure is the same

          \frac{F_1}{A_1} = \frac{F_2}{A_2}

where subscript 1 is for the small piston and subscript 2 is for the large piston

          F₁ = \frac{A_1}{A_2} \ F_2

the force applied must be equal to the weight of the truck

          F₁ = ( \frac{d_1}{d_2} )^2\  m g

          F₁ = (0.05 / 1) ² 5000 9.8

          F₁ = 122.5 N

7 0
2 years ago
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