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klemol [59]
3 years ago
13

In the early 19th century Christian Doppler, an Austrian physicist, proposed a theory regarding the properties of a moving sourc

e of sound. This is now known as Doppler’s law or the Doppler effect. What does this law state?
Physics
2 answers:
svlad2 [7]3 years ago
6 0

The answer is D) The frequency of a moving source of sound is greater as it approaches an observer.

vovangra [49]3 years ago
5 0
<span>The Doppler effect is the effect produced by a source of sound waves that is moving relative to an observer. There sound will have a higher pitch as it approaches the observer, and a lower pitch as iits moves away from the observer. The effect is commonly experienced as an ambulance passes.</span>
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Find average speed when time= 27s and total distance is 94m
Slav-nsk [51]
3.4814815 (or 3 13/27) m/s

speed = distance/time
3.4814815 (or 3 13/27) = 94/27

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3 years ago
The speed of propagation of the action potential (an electrical signal) in a nerve cell depends (inversely) on the diameter of t
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Answer:

Explanation:

Speed of electrical nerve signal = 33 m /s

Distance travelled = 1.3 m

time taken = distance / speed

= 1.3 / 33  

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2 years ago
True or false question please help me out
Len [333]

Answer:

thats true

Explanation:

7 0
2 years ago
Squids and octopuses propel themselves by expelling water. They do this by keeping water in a cavity and then suddenly contracti
Alex

Answer:

A) The speed of the water must be 8.30 m/s.

B) Total kinetic energy created by this maneuver is 70.12 Joules.

Explanation:

A) Mass of squid with water = 6.50 kg

Mass of water in squid cavuty = 1.55 kg

Mass of squid = m_1=6.50 kg- 1.55 kg=4.95 kg

Velocity achieved by squid = v_1=2.60 m/s

Momentum gained by squid = P=m_1v_1

Mass of water = m_2=1.55 kg

Velocity by which water was released by squid = v_2

Momentum gained by water but in opposite direction = P'=m_2v_2

P = P'

m_1v_1=m_2v_2

v_2=\frac{m_1v_1}{m_2}=\frac{4.95 kg\times 2.60 m/s}{1.55 kg}=8.30 m/s

B) Kinetic energy does the squid create by this maneuver:

Kinetic energy of squid = K.E  =\frac{1}{2}m_1v_1^{2}

Kinetic energy of water = K.E' = \frac{1}{2}m_2v_2^{2}

Total kinetic energy created by this maneuver:

K.E+K.E'=\frac{1}{2}m_1v_1^{2}+\frac{1}{2}m_2v_2^{2}

=\frac{1}{2}\times 4.95 kg\times (2.60 m/s)^2+\frac{1}{2}\times 1.55 kg\times (8.30 m/s)^2=70.12 Joules

4 0
3 years ago
Determine the kinetic energy of 1000-kg roller coaster car that is moving with speed of 20.0m/s
nevsk [136]
B, i got the same question
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3 years ago
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