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dimulka [17.4K]
2 years ago
8

The center of mass of the system is the point at which the total mass of the system could be concentrated without changing the _

___________.
Physics
1 answer:
Sveta_85 [38]2 years ago
8 0

  The centre of mass of the system is the point at which the total

  mass of system could be concentrated without changing the moment

  of the system.

Centre of Mass is the point at which the whole mass of the system

is assumed to be concentrated.

 The general formula for the COM is:

              xₙ =  Σmₐxₐ / Σmₐ         where,  a = 1,2,3.........n

  Here the term Σ mₐ xₐ is called the first moment of the system and the

  denominator expression is called total mass of the system.

    Therefore, from this theory we can say that the moment of the system

    remain unchanged while calculating the COM.

  Hence, The centre of mass of the system is the point at which the total

  mass of system could be concentrated without changing the moment

  of the system.

   learn more about centre of mass here:

             brainly.com/question/3454419

                #SPJ4

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you can produce a sound by plucking a string or by blowing in a pipe. how are these two ways different?​
Shkiper50 [21]

Answer:

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4 0
3 years ago
A golf ball is hit so that it leaves the club face at a velocity of 45m/s at an angle of 40° to the horizontal. by ignoring the
tatuchka [14]

Answer:a)45cos40 b)45sin40 c) 2.95 d)102

Explanation:

a) v_{x} = 45 cos40

b) v_{y}=45sin40

c) Since air resistance is negligible, the only force acting on the golf ball is gravity. Thus, its vertical acceleration is -<em>g</em>. We know the final velocity must be 0 m/s, because this will be when the golf ball reaches the maximum height and starts to change direction (it falls back to the ground). We also know initial velocity in the vertical direction (see part b). Thus, we can use this equation: v_{f} = v_{i} + at.

0 m/s = 45sin40 + (-9.8m/s^2)t\\t = 2.95s

d) The horizontal distance traveled is dependent on (1) how long the ball is in the air and (2) what the horizontal velocity is. (1) was found in part c, and (2) was found in part a.

x=vt\\x=45cos40(2.95) =102m

6 0
2 years ago
For an object like a planet, with a typical temperature of a few hundred kelvin, what kind of blackbody radiation would it princ
navik [9.2K]

Answer:

Low-temperature blackbody

Explanation:

There are 3 types of blackbody temperatures.

Low-temperature blackbody

High temperature extended area blackbody

High-temperature cavity blackbody

A Low-temperature blackbody is a type of black body radiation that has the range of -40° C to 175° C, typically between 233 K and 448 K. A perfect fit for the temperature range mentioned in the question, "a few hundred Kelvin". Therefore, it's the kind of blackbody temperature that the object would emit.

6 0
3 years ago
A constant current of I = 15 A exists in a solenoid whose inductance is L = 2.8 H. The current is then reduced to zero in a cert
julia-pushkina [17]

Answer:

Explanation:

Given that

Constant current I=15A

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∆I=0-15=-15

For a time of t=75ms=0.075s

EMF=?

EMF is given at

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b. Energy stored?

Energy stored is given as

E=½LI²

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c. Rate of energy? Which is power and the rate of energy is given as

Power=Energy/timetaken

Power=315/0.075

Power=4200W

P=4.2KW

7 0
3 years ago
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