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3 years ago

3x^2 - 4x + 7 (Find the domain of the expression)

Mathematics

1 answer:

Jobisdone [24]3 years ago

3 0

x1 = −(−4) − √ (−4)2 − 4×3×7 2×3 = 4 − 2 × √ 17 i 6 ≈ 0.666667 − 1.374369ix2 = −(−4) + √ (−4)2 − 4×3×7 2×3 = 4 + 2 × √ 17 i 6 ≈ 0.666667 + 1.374369i

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Please help its easy just i'm dvmb, just need this for my homework real soon!.. DON'T MIND THOSE ANSWERS SELECTED!!!!

trasher [3.6K]

<h3>Hey there today we will solve your problem,</h3>

Number 1

_______________

<h3>Definitions</h3>

Vertical angles - either of two angles lying on opposite sides of two intersecting lines.

Linear Pair - A linear pair is a pair of adjacent angles formed when two lines intersect.

_______________

Now we can solve Number 1, there is one pair of Vertical angles being ∠5 and ∠3

_______________

Number 2

Since we know the definition of a Linear Pair we can solve this problem also, the only Linear Pair that we can choose out the ones give to us is ∠4 and ∠3, because they are adjacent.

_______________

${\huge{\boxed{\mathfrak{Answer}}}$

∠5 and ∠3

2. ∠4 and ∠3

8 0

2 years ago

Write the polynomial in standard form. Then name the polynomial on its degree and numbers of terms. 8-4x^2+10x^2+2x

mojhsa [17]

8-4x^2+10x^2+2x
8+6x^2+2x
6x^2+2x+8

This is a quadratic equation since it has three terms. Now, a=6 (that is, a≠0) and therefore, it is a quadratic trinomial equation.

The correct answer is C.)

6 0

3 years ago

Estimate the product by rounding 2 x 6,254

Pavlova-9 [17]

5 × 6,254= 31,300 is the awnser :)

6 0

3 years ago

Forty percent of households say they would feel secure if they had $50,000 in savings. you randomly select 8 households and ask

Kay [80]

Answer:

Let X be the event of feeling secure after saving $50,000,

Given,

The probability of feeling secure after saving $50,000, p = 40 % = 0.4,

So, the probability of not feeling secure after saving $50,000, q = 1 - p = 0.6,

Since, the binomial distribution formula,

$P(x=r)=^nC_r p^r q^{n-r}$

Where, $^nC_r=\frac{n!}{r!(n-r)!}$

If 8 households choose randomly,

That is, n = 8

(a) the probability of the number that say they would feel secure is exactly 5

$P(X=5)=^8C_5 (0.4)^5 (0.6)^{8-5}$

$=56(0.4)^5 (0.6)^3$

$=0.12386304$

(b) the probability of the number that say they would feel secure is more than five

$P(X>5) = P(X=6)+ P(X=7) + P(X=8)$

$=^8C_6 (0.4)^6 (0.6)^{8-6}+^8C_7 (0.4)^7 (0.6)^{8-7}+^8C_8 (0.4)^8 (0.6)^{8-8}$

$=28(0.4)^6 (0.6)^2 +8(0.4)^7(0.6)+(0.4)^8$

$=0.04980736$

(c) the probability of the number that say they would feel secure is at most five

$P(X\leq 5) = P(X=0) + P(X=1) + P(X=2) + P(X=3) + P(X=4) + P(X=5)$

$=^8C_0 (0.4)^0(0.6)^{8-0}+^8C_1(0.4)^1(0.6)^{8-1}+^8C_2 (0.4)^2 (0.6)^{8-2}+8C_3 (0.4)^3 (0.6)^{8-3}+8C_4 (0.4)^4 (0.6)^{8-4}+8C_5(0.4)^5 (0.6)^{8-5}$