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tankabanditka [31]
3 years ago
9

How does the graph of g (x) = StartFraction 1 Over x + 4 EndFraction minus 6 compare to the graph of the parent function f (x) =

StartFraction 1 Over x EndFraction?
Mathematics
2 answers:
sladkih [1.3K]3 years ago
7 0

Answer:

the graph is shifted 4 units to the left and 6 units down.

I took the test!

rjkz [21]3 years ago
6 0

The transformed equation  $g(x)=\frac{1}{x+4}-6$ , the graph is shifted 4 units to the left and 6 units down.

Explanation:

The parent equation is $f(x)=\frac{1}{x}$

The transformed equation is $g(x)=\frac{1}{x+4}-6$

By using the function transformation rules, we can see that the parent function $f(x)=\frac{1}{x}$ is transformed into the function $g(x)=\frac{1}{x+4}-6$

Since, from the function transformation rules, we know that,

$f(x+b)$ shifts the function b units to the left.

Thus, the transformed function is shifted 4 units to the left.

Also,  from the function transformation rules, we know that,

$f(x)-b$ shifts the function b units downward.

Thus, the transformed function is shifted 6 units down.

Thus, the transformed equation  $g(x)=\frac{1}{x+4}-6$ , the graph is shifted 4 units to the left and 6 units down.

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Find the slope of the line that passes through (-37, 47) and (26, 32).
stiks02 [169]
(x1,y1) = (-37,47)
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3 years ago
PWEASE HELP ASAP my friends and I cant figure this out I'm hoping one of u guys can
Degger [83]

The number of viruses was 4000 times greater than number of protozoa.

Step-by-step explanation:

Given,

Number of protozoa = 5*10^5

Number of viruses = 2*10^9

Let,

x be the number of times number of viruses is greater than number of protozoa.

Number of viruses = Number of time * Number of protozoa

2*10^9=(5*10^5)x

Dividing both sides by 5*10^5

\frac{2*10^9}{5*10^5}=\frac{(5*10^5)x}{5*10^5}\\\\4*10^3= x\\x=4*10^3 \\x=4000

The number of viruses was 4000 times greater than number of protozoa.

Keywords: division, scientific notation

Learn more about division at:

  • brainly.com/question/10046556
  • brainly.com/question/100704

#LearnwithBrainly

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