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PilotLPTM [1.2K]
3 years ago
12

Determine the eccentricity, the type of conic, and the directrix for r = 9/1+6 cos theta. (Picture Provided Below)

Mathematics
2 answers:
GalinKa [24]3 years ago
6 0

Answer:

Eccentricity = 6

Type of conic section; Hyperbola

Directrix; x = 3/2

Step-by-step explanation:

The given polar equation of the conic section is in standard form;

The eccentricity is given by the coefficient of cos theta in which case this would be the value 6. Therefore, the eccentricity of the this conic section is 6.

The eccentricity is clearly greater than 1, implying that the conic section is a Hyperbola.

Since the conic section is in standard form, the numerator is the product of eccentricity and the value of the directrix, that is;

e*d = 9

6*d = 9

d = 3/2.

Since the denominator has a plus sign then the hyperbola opens towards the left and thus the equation of its directrix is;

x = 3/2

wlad13 [49]3 years ago
6 0

Answer: Option D

Eccentricity = 6

Type of conic section; Hyperbola

Directrix; x = 3/2

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Given:

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Juan runs out of gas in a city. He walks 4 yards west and then 3 yards south looking for a gas station How far
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A line that passes through the points (–4, 10) and (–1, 5) can be represented by the equation y = (x – 2). Which equations also
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The equation y=x-2 do not represents the line that passes through the two point, since for example -4-2=-6, not 10. So (-4,10) is not on the line. 
Let find the equation of the line:
First compute the slope using formula:
<span> </span>\frac{y_2-y_1}{x_2-x_1}= \frac{5-10}{-1-(-4)}= \frac{-5}{3}
So the equation is in the form:
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The equation then is the following:
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3 years ago
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yKpoI14uk [10]

Answer: 105 degrees

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