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PilotLPTM [1.2K]
3 years ago
12

Determine the eccentricity, the type of conic, and the directrix for r = 9/1+6 cos theta. (Picture Provided Below)

Mathematics
2 answers:
GalinKa [24]3 years ago
6 0

Answer:

Eccentricity = 6

Type of conic section; Hyperbola

Directrix; x = 3/2

Step-by-step explanation:

The given polar equation of the conic section is in standard form;

The eccentricity is given by the coefficient of cos theta in which case this would be the value 6. Therefore, the eccentricity of the this conic section is 6.

The eccentricity is clearly greater than 1, implying that the conic section is a Hyperbola.

Since the conic section is in standard form, the numerator is the product of eccentricity and the value of the directrix, that is;

e*d = 9

6*d = 9

d = 3/2.

Since the denominator has a plus sign then the hyperbola opens towards the left and thus the equation of its directrix is;

x = 3/2

wlad13 [49]3 years ago
6 0

Answer: Option D

Eccentricity = 6

Type of conic section; Hyperbola

Directrix; x = 3/2

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the sum of 16 numbers is 240.The average of 6 of those numbers is 10. the average of the remaining numbers is
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Answer:

18

Step-by-step explanation:

If the average of 6 numbers is 10, then the sum of those 6 numbers is:

6 x 10 = 60

To calculate the sum of the remaining 10 numbers, subtract 60 from the total sum of all the numbers:

240 - 60 = 180

Therefore, the average of the 10 remaining numbers:

180 ÷ 10 = 18

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The factored from of a polynomial can be found from the zeros or x-intercepts of the graph.

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