Question

Balance the following equation for the combustion of methane (3 pts):

Answer 1

Answer:

$\huge \boxed{\mathrm{CH_4+ 2O_2 \Rightarrow CO_2 +2 H_2O}}$

$\rule[225]{225}{2}$

Explanation:

$\sf CH_4+ O_2 \Rightarrow CO_2 + H_2O$

Balancing the Hydrogen atoms on the right side,

$\sf CH_4+ O_2 \Rightarrow CO_2 +2 H_2O$

Balancing the Oxygen atoms on the left side,

$\sf CH_4+ 2O_2 \Rightarrow CO_2 +2 H_2O$

$\rule[225]{225}{2}$

Answer 2

Answer:

The balance chemical equation of combustion of methane is:

$CH_4 + 2O_2\rightarrow CO_2 + 2H_2O$

Explanation:

[tex]CH_4 + O_2\rightarrow CO_2 + H_2O[/tex]

During balancing of the chemical reaction balance out all the elements beside oxygen. Oxygen atom should always be balanced in the end.

$CH_4 + O_2\rightarrow CO_2 + H_2O$

On reactant side :

C = 1, H = 4, O = 2

On product side :

C = 1, H = 2, O = 3

Step 1 : Write 2 in front of water.

$CH_4 + O_2\rightarrow CO_2 + 2H_2O$

Step 2 : Write 3 in front of oxygen.

$CH_4 + 2O_2\rightarrow CO_2 + 2H_2O$

On reactant side :

C = 1, H = 4, O = 4

On product side :

C = 1, H = 4, O = 4

Chemical equation is balanced.