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3 years ago

Help me!!!What is the Hydronium and Hydroxide for the substances

Chemistry

1 answer:

Lyrx [107]3 years ago

3 0

Answer:

from the ph given find the negative of log of concentrations of hydrogen and hydroxyl ions in acid and base respectively..then write tghe no. of moles of hydrogen and hydroxide ions

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Write a balanced equation to show the reaction of gaseous ethane with gaseous oxygen to form carbon monoxide gas and water vapor

Korolek [52]

7 0

4 years ago

A gas with volume of 700.0 mL at STP (0.0 0C, 1.00 atm) is compressed to a volume of 200.0 mL and the temperature is increased t

tekilochka [14]

Answer:

393.1 KPa

Explanation:

Now we have to use the general gas equation;

P1V1/T1 = P2V2/T2

P1= initial pressure of the gas= 1.00atm

V1 = initial volume= 700.0 ml

T1= initial temperature= 0.0°C +273= 273K

V2= final volume= 200.0 ml

T2= final temperature =30.0°C +273= 303 K

P2= final pressure =????

Therefore;

P2= P1V1T2/ V2T1

P2= 1.00 × 700.0 × 303/ 200.0 × 273

P2= 3.88 atm

But

1 atm = 101.325 kilopascals

Therefore 3.88 atm = 3.88 × 101.325 kilopascals = 393.1 KPa

6 0

3 years ago

The bus will stop here into question tag

Vikentia [17]

Answer:

Huh????????????????????

7 0

3 years ago

PLEASE HELP CHEM BABES I HAVE BEEN CRYING FOR A WHILE NOW

slavikrds [6]

Answer: See below

Explanation:

1. To calculate the mass, you know you can convert by using molar mass. Since mass is in grams, we can use molar mass to convert moles to grams. This calls for the Ideal Gas Law.

Ideal Gas Law: PV=nRT

We manipulate the equation so that we are solving for moles, then convert moles to grams.

n=PV/RT

P= 100 kPa

V= 0.831 L

R= 8.31 kPa*L/mol*K

T= 27°C+273= 300 K

Now that we have our values listed, we can plug in to find moles.

$n=\frac{(100kPa)(0.831L)}{(8.31kPa*l/molK)(300K)}$

$n=0.033mol$

We use the molar mass of NO₂ to find grams.

$0.033mol*\frac{46.005g}{1mol }=1.52 g$

The mass is 1.52 g.

2. To calculate the temperature, we need to use the Ideal Gas Law.

Ideal Gas Law: PV=nRT

We can manipulate the equation so that we are solving for temperature.

T=PV/nR

P= 700.0 kPa

V= 33.2 L

R= 8.31 kPa*L/mol*K

n= 70 mol

Now that we have our values, we can plug in and solve for temperature.

$T=\frac{(700kPa)(33.2L)}{(70mol)(8.31 kPa*L/molK)}$

$T=40K$

The temperature is 40 K.

3 0

3 years ago

Nascar fans love race day when they get a chance to cheer on there favorite racer if a driver was able to travel 600 miles in 3

hjlf

Answer:

200 mph

Explanation:

600/3=200

5 0

3 years ago