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makvit [3.9K]
3 years ago
10

Draw a Lewis structure for O3 in which the central O atom obeys the octet rule, and answer the following questions based on your

drawing. The number of unshared pairs (lone pairs) on the central O atom is: The central O atom forms single bonds. The central O atom forms double bonds.

Chemistry
1 answer:
Juli2301 [7.4K]3 years ago
8 0

Answer:

The unpaired electron pair on central atom = 1

The central atom form 1 single bond 1 double bond with oxygen atoms.

Explanation:

Ozone, O_3

Valence electrons of oxygen = 6

Only the valence electrons are shown by dots in the Lewis structure.

The Lewis structure is shown in the image below.

From the Lewis structure, it can be concluded that:-

The unpaired electron pair on central atom = 1

The central atom form 1 single bond 1 double bond with oxygen atoms.

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22.5 g of silver nitrate reacts with excess magnesium bromide, determine the mass
Setler [38]

Answer:

9.82 g of Mg(NO₃)₂

Explanation:

Let's determine the reaction:

2AgNO₃  +  MgBr₂  → Mg(NO₃)₂  +  2AgBr

2 moles of nitrate silver reacts with MgBr₂ in order to produce 1 mol of magnesium nitrate and silver bromide.

We determine the moles of AgNO₃

22.5 g . 1mol / 169.87g = 0.132 moles

Ratio is 2:1.

2 moles of silver nitrate can produce 1 mol of magnesium nitrate

Then, our 0.132 moles may produce (0.132 . 1)/ 2 = 0.0662 moles

We convert moles to mass:

0.0662 mol . 148.3 g/ mol = 9.82 g

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Elza [17]

Answer:

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Explanation:

Between the options given, argon gas is the least reactive. Argon is known as a <em>noble gas</em>, this means that it is located in the group 18 in the periodic table. These gases are known for their low reactivity, under most circumstances.

The <u>electronic configuration</u> of argon helps us see why that is the case: With an atomic number of 18, it has an electronic configuration of 1s² 2s² 2p⁶ 3s² 3p⁶. This means the most external orbital is filled with electrons, meaning that there are not unpaired electrons able to react with other substances.

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Explanation:

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Answer:

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