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stiks02 [169]
3 years ago
13

I need to know the correct trigonometric ratios that could be sued to determine the length of LN

Mathematics
1 answer:
Artemon [7]3 years ago
4 0

Answer:

A, E

Step-by-step explanation:

Remember SOH-CAH-TOA:

Sine = Opposite / Hypotenuse

Cosine = Adjacent / Hypotenuse

Tangent = Opposite / Adjacent

Therefore, we can say:

sin 20° = LN / 8

cos 70° = LN / 8

tan 70° = MN / LN

Only the first and last options are correct.

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The diameter of a circle is 6 in. Find its area to the nearest tenth.
Marrrta [24]

Answer and Step-by-step explanation:

The area formula for a Circle is:

A = \pi r^2

Diameter is equal to the radius times 2.

<u>So, divide the diameter to get the radius.</u>

6 divided by 2 equals 3.

<u>Now, plug it into the formula.</u>

A = \pi (3)^{2}

A = 9\pi

Plug this into your calculator by multiplying 9 by pi.

<u>We get the answer to be 28.3 when rounded to the nearest tenth.</u>

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<em><u>#teamtrees #PAW (Plant And Water)</u></em>

8 0
2 years ago
The diameter of a sphere is 42 centimeters. find the surface area to the nearest tenth
Mademuasel [1]
A ~ 5541.77cm squared
8 0
3 years ago
What is the next term of the arithmetic sequence? -7,-3,1,5,9,
inessss [21]

Answer:

The next term is 13.

Step-by-step explanation:

Looking at the previous numbers...

for -7 to get to -3, you have to add 4, and for -3 to get to 1 you have to add 4.... and so on. So in order to find the next number, add 4 to 9, and which you get 13.

3 0
3 years ago
Read 2 more answers
Without plotting points, let M=(-2,-1), N=(3,1), M'= (0,2), and N'=(5, 4). Without using the distanceformula, show that segments
kramer

Given:

M=(x1, y1)=(-2,-1),

N=(x2, y2)=(3,1),

M'=(x3, y3)= (0,2),

N'=(x4, y4)=(5, 4).

We can prove MN and M'N' have the same length by proving that the points form the vertices of a parallelogram.

For a parallelogram, opposite sides are equal

If we prove that the quadrilateral MNN'M' forms a parallellogram, then MN and M'N' will be the oppposite sides. So, we can prove that MN=M'N'.

To prove MNN'M' is a parallelogram, we have to first prove that two pairs of opposite sides are parallel,

Slope of MN= Slope of M'N'.

Slope of MM'=NN'.

\begin{gathered} \text{Slope of MN=}\frac{y2-y1}{x2-x1} \\ =\frac{1-(-1)}{3-(-2)} \\ =\frac{2}{5} \\ \text{Slope of M'N'=}\frac{y4-y3}{x4-x3} \\ =\frac{4-2}{5-0} \\ =\frac{2}{5} \end{gathered}

Hence, slope of MN=Slope of M'N' and therefore, MN parallel to M'N'

\begin{gathered} \text{Slope of MM'=}\frac{y3-y1}{x3-x1} \\ =\frac{4-(-1)}{5-(-2)} \\ =\frac{3}{2} \\ \text{Slope of NN'=}\frac{y4-y2}{x4-x2} \\ =\frac{4-1}{5-3} \\ =\frac{3}{2} \end{gathered}

Hence, slope of MM'=Slope of NN' nd therefore, MM' parallel to NN'.

Since both pairs of opposite sides of MNN'M' are parallel, MM'N'N is a parallelogram.

Since the opposite sides are of equal length in a parallelogram, it is proved that segments MN and M'N' have the same length.

7 0
1 year ago
if a rental car agency charges $17 per day plus 10 cents per mile to rent a certain car.Another agency charges $21 per day plus
SashulF [63]
17+(10X)= 21+(5x) is the equation
17 +(10x1)= 21+(5x1)
17+10=21+5
27=27
So your answer is it takes 1 mile per day
Hope its right lol
7 0
3 years ago
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