Answer:
Step-by-step explanation:
If you call "5x-2x^2+1" an "equation," then you must equate 5x-2x^2+1 to 0:
5x-2x^2+1 = 0
This is a quadratic equation. Rearranging the terms in descending order by powers of x, we get:
-2x^2 + 5x + 1 = 0. Here the coefficients are a = -2, b = 5 and c = 1.
Use the quadratic formula to solve for x:
First find the discriminant, b^2 - 4ac: 25 - 4(-2)(1) = 25 + 8 = 33
Because the discriminant is positive, the roots of this quadratic are real and unequal.
-b ± √(discriminant)
Applying the quadratic formula x = --------------------------------
2a
we get:
-5 ± √33 -5 + √33
x = ----------------- = --------------------- and
2(-2) -4
-5 - √33
---------------
-4
Answer:
Step-by-step explanation:
Let's write the left hand side as a negative power, and 9 as a power of 3:
At this point, for the equality to still stand, the exponents have to be equal:
1- it’s
2- it’s
3- let’s
4- one’s
5- he’s
<span>✡ Answer: 9000 </span><span>✡
- - Solve:
If your 3 numbers to the right (in this problem its 3) are 499 or less, you round down, if its 500 or up, you round up.
In this case, round up.
- - Solve furthermore:
9000
</span>
✡Hope this helps<span>✡</span>
School is dumb....................................
