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Naily [24]
4 years ago
10

A 50 kg diver stands motionless at the top of 10.0 meter high dive. What is her potential energy?

Engineering
1 answer:
brilliants [131]4 years ago
7 0

Answer:

Potential energy=4905 Joule

Explanation:

Potential energy is defined as the energy between two bodies due to its relative positions. Here one body is the diver and the other body is the earth. So acceleration will be the constant 9.81\ m/s^2

P.E.=m\times g\times h\\where\ m=mass\ of\ body=50\ kg\\g=acceleration\ due\ to\ gravity=9.81\ m/s^2\\h=height\ at\ which\ the\ body\ is\ from\ the\ ground=10.0\ m\\\Rightarrow P.E.=50\times 9.81\times 10.0\\\therefore Potential\ Energy=4905\ Joule

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The magic square is an arrangement of numbers in a square grid in such a way that the sum of the numbers in each row, and in eac
Yuki888 [10]

Answer:

See the explanation for the answer;

Explanation:

Matlab code is as given below

-------------------------------------------------------------------------------------Start of code

% Program to create a magic square and verify it

clc

M= magic(5)

% To find sum of elements of each row

r1= sum(M(1,:))      % Sum of row 1

r2= sum(M(2,:))      % Sum of row 2

r3= sum(M(3,:))      % Sum of row 3

r4= sum(M(4,:))      % Sum of row 4

r5= sum(M(5,:))      % Sum of row 5

% To find sum of each coloumn

c1= sum(M(:,1))      % Sum of coloumn 1

c2= sum(M(:,2))      % Sum of coloumn 2

c2= sum(M(:,3))      % Sum of coloumn 3

c2= sum(M(:,4))      % Sum of coloumn 4

c2= sum(M(:,5))      % Sum of coloumn 5

% To find sum of diagonal

d1= sum(diag(M))               % Sum of principal diagonal elements

d2= sum(diag(fliplr(M)))      

-------------------------------------------------------------------------------End of code

Following results are obtained when executed.

M =

   17    24     1     8    15

   23     5     7    14    16

    4     6    13    20    22

   10    12    19    21     3

   11    18    25     2     9

r1 =

   65

r2 =

   65

r3 =

   65

r4 =

   65

r5 =

   65

c1 =

   65

c2 =

   65

c2 =

   65

c2 =

   65

c2 =

   65

d1 =

   65

d2 =

   65

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alexandr402 [8]
A.

It would be released without a doubt so be careful!

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5 0
4 years ago
An alternating current is supplied to an electronic component with a rating that it be used only for voltages below 12 V. What i
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Answer:

V_{rms}=6\sqrt2\ V

Explanation:

Given that,

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Let rms voltage in terms of peak voltage is given by :

V_{rms}=\dfrac{V}{\sqrt2}\\\\=\dfrac{12}{\sqrt2}\\\\=\dfrac{12}{\sqrt2}\times \dfrac{\sqrt2}{\sqrt2}\\\\=\dfrac{12\sqrt2}{2}\\\\=6\sqrt2\ V

Hence, the required rms voltage is 6\sqrt2\ V.

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