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Naily [24]
4 years ago
10

A 50 kg diver stands motionless at the top of 10.0 meter high dive. What is her potential energy?

Engineering
1 answer:
brilliants [131]4 years ago
7 0

Answer:

Potential energy=4905 Joule

Explanation:

Potential energy is defined as the energy between two bodies due to its relative positions. Here one body is the diver and the other body is the earth. So acceleration will be the constant 9.81\ m/s^2

P.E.=m\times g\times h\\where\ m=mass\ of\ body=50\ kg\\g=acceleration\ due\ to\ gravity=9.81\ m/s^2\\h=height\ at\ which\ the\ body\ is\ from\ the\ ground=10.0\ m\\\Rightarrow P.E.=50\times 9.81\times 10.0\\\therefore Potential\ Energy=4905\ Joule

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Answer:

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Explanation:

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3 years ago
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what i the maximum flow rate of glycerine at 20C in a 10cm diameter pipe that can be assumed to remain laminar
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Answer: tube flow

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Calculate the viscosity(dynamic) and kinematic viscosity of airwhen
nikitadnepr [17]

Answer:

(a) dynamic viscosity = 1.812\times 10^{-5}Pa-sec

(b) kinematic viscosity = 1.4732\times 10^{-5}m^2/sec

Explanation:

We have given temperature T = 288.15 K

Density d=1.23kg/m^3

According to Sutherland's Formula  dynamic viscosity is given by

{\mu} = {\mu}_0 \frac {T_0+C} {T + C} \left (\frac {T} {T_0} \right )^{3/2}, here

μ = dynamic viscosity in (Pa·s) at input temperature T,

\mu _0= reference viscosity in(Pa·s) at reference temperature T0,

T = input temperature in kelvin,

T_0 = reference temperature in kelvin,

C = Sutherland's constant for the gaseous material in question here C =120

\mu _0=4\pi \times 10^{-7}

T_0 = 291.15

\mu =4\pi \times 10^{-7}\times \frac{291.15+120}{285.15+120}\times \left ( \frac{288.15}{291.15} \right )^{\frac{3}{2}}=1.812\times 10^{-5}Pa-swhen T = 288.15 K

For kinematic viscosity :

\nu = \frac {\mu} {\rho}

kinemic\ viscosity=\frac{1.812\times 10^{-5}}{1.23}=1.4732\times 10^{-5}m^2/sec

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The following data were obtained when a cold-worked metal was annealed. (a) Estimate the recovery, recrystallization, and grain
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A 600 MW power plant has an efficiency of 36 percent with 15
ololo11 [35]

Answer:

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q2 = 0.64 * q1

p = 0.36 * q1

q1 = p /0.36

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qw = 0.85 *0.64/0.36 * p

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In evaporation water becomes vapor absorbing heat without going to the boiling point (similar to how sweating takes heat from the human body)

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