Answer:
τ = 0.25 lbf/in²
Explanation:
given that the oil viscosity, μ = 2.415 lb/ft-s
gap between plates = 1/4 inches = 1/4*12 = 1/48 ft
recall from newtons law of viscosity;
shear stress τ = μ du/dy =
τ = (2.415 lb/ft-s) (10 ft/s)/(1/48) ft
τ = 1159.2 lb/ft-s²
we know that, 1 slug = 32.174 lb
lb = 1/32.174 slug
∴ τ = 1159.2/32.174 slug/ft-s² = 36 slug/ft-s²
τ = 36 slug/ft-s²
multiply both the numerator and denominator by ft, this gives
τ = 36 slug-ft/ft²-s²
τ = 36 lbf/ft² where 1 slug-ft/s² = 1lbf
since 1 ft = 12 inch = 1 ft² = 12² in² = 144 in²
∴ τ = 36/144 lbf /in² = 0.25 lbf/in²
τ = 0.25 lbf/in²
Answer:
8.419 million (2019) at 2019
Is this even a question ?
Answer:
a) 4160 V
b) 12 kW and 81 kVAR
c) 54 kW and 477 kVAR
Explanation:
1) The phase voltage is given as:

The complex power S is given as:


The line current I is given as:

The phase voltage at the sending end is:

The magnitude of the line voltage at the source end of the line (
b) The Total real and reactive power loss in the line is:

The real power loss is 12000 W = 12 kW
The reactive power loss is 81000 kVAR = 81 kVAR
c) The sending power is:

The Real power delivered by the supply = 54000 W = 54 kW
The Reactive power delivered by the supply = 477000 VAR = 477 kVAR
Answer:
The velocity of flow is 10.0 m/s.
Explanation:
We shall use Manning's equation to calculate the velocity of flow
Velocity of flow by manning's equation is given by

where
n = manning's roughness coefficient
R = hydraulic radius
S = bed slope of the channel
We know that for an asphalt channel value of manning's roughness coefficient = 0.016
Applying values in the above equation we obtain velocity of flow as
