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2 years ago

12

An agricultural manager requires

1 answer:

sp2606 [1]2 years ago

3 0

C, being able to maintain legal information on grant programs

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A long corridor has a single light bulb and two doors with light switch at each door.

Tpy6a [65]

Answer:

Light = A xor B

Explanation:

If switches A and B produce True or False, then Light will be True for ...

Light = A xor B

8 0

3 years ago

vertical gate in an irrigation canal holds back 12.2 m of water. Find the average force on the gate if its width is 3.60 m. Repo

DanielleElmas [232]

Answer:

The right solution is "2625 kN".

Explanation:

According to the question,

The average pressure will be:

= $density\times g\times \frac{h}{2}$

By putting values, we get

= $1000\times 9.8\times \frac{12.2}{2}$

= $1000\times 9.8\times 6.1$

= $59780$

hence,

The average force will be:

= $Pressure\times Area$

= $59780\times 3.6\times 12.2$

= $2625537 \ N$

Or,

= $2625 \ kN$

5 0

2 years ago

An object of mass 521 kg, initially having a velocity of 90 m/s, decelerates to a final velocity of 14 m/s. What is the change i

Harman [31]

Answer:2058.992KJ

Explanation:

Given data

Mass of object $\left ( m\right )$ =521kg

initial velocity $\left ( v_0\right )$ =90m/s

Final velocity $\left ( v\right )$ =14m/s

kinetic energy of body is given by= $\frac{1}{2}$ $m$ $v^{2}$

change in kinectic energy is given by substracting final kinetic energy from initial kinetic energy of body.

Change in kinetic energy= $\frac{1}{2}\times m$ $\left ( V_0^{2}-V^2\right )$

Change in kinetic energy= $\frac{1}{2}\times521$ $\left ( 90^{2}-14^2\right )$

Change in kinetic energy=2058.992KJ

7 0

3 years ago

If you need to write a function that will compute the cost of some candy, where each piece costs 25 cents, which would be an app

masya89 [10]

The best answer would be

D. Int calculateCost(int count);

6 0

3 years ago

In a tensile test on a steel specimen, true strain = 0.12 at a stress of 250 MPa. When true stress = 350 MPa, true strain = 0.26

scZoUnD [109]

Answer:

The strength coefficient is $625$ and the strain-hardening exponent is $0.435$

Explanation:

Given the true strain is 0.12 at 250 MPa stress.

Also, at 350 MPa the strain is 0.26.

We need to find $(K)$ and the $(n)$ .

$\sigma =K\epsilon^n$

We will plug the values in the formula.

$250=K\times (0.12)^n\\350=K\times (0.26)^n$

We will solve these equation.

$K=\frac{250}{(0.12)^n}$ plug this value in $350=K\times (0.26)^n$

$350=\frac{250}{(0.12)^n}\times (0.26)^n\\ \\\frac{350}{250}=\frac{(0.26)^n}{(0.12)^n}\\ \\1.4=(2.17)^n$

Taking a natural log both sides we get.

$ln(1.4)=ln(2.17)^n\\ln(1.4)=n\times ln(2.17)\\n=\frac{ln(1.4)}{ln(2.17)}\\ n=0.435$

Now, we will find value of $K$

$K=\frac{250}{(0.12)^n}$

$K=\frac{250}{(0.12)^{0.435}}\\ \\K=\frac{250}{0.40}\\\\K=625$

So, the strength coefficient is $625$ and the strain-hardening exponent is $0.435$ .

5 0

3 years ago