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Aliun [14]
3 years ago
13

Don't break or crush mercury-containing lamps because mercury powder may be released.

Engineering
1 answer:
alexandr402 [8]3 years ago
5 0
A.

It would be released without a doubt so be careful!

Hope this helps :)
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As the driver of the red SUV, what are your options for navigating this roundabout?
IgorC [24]

Your options for navigating this roundabout would include driving in a counter-clockwise direction and then making your exit to the right lane.

<h3>What is a roundabout? </h3>

A roundabout is a circular intersection that make junctions or intersections of roads safer, because it is designed and developed to physically direct drivers and pedestrians to move in a counter-clockwise direction.

In this scenario, your options for navigating this roundabout as the driver of the red SUV would include driving in a counter-clockwise direction and then making your exit to the right lane.

Read more on roundabout here: brainly.com/question/22580476

#SPJ1

3 0
2 years ago
When the compression process is non-quasi-equilibrium, the molecules before the piston face cannot escape fast enough, forming a
muminat

Answer:

a. true

Explanation:

Firstly, we need to understand what takes places during the compression process in a quasi-equilibrium process. A quasi-equilibrium process is a process in during which the system remains very close to a state of equilibrium at all times.  When a compression process is quasi-equilibrium, the work done during the compression is returned to the surroundings during expansion, no exchange of heat, and then the system and the surroundings return to their initial states. Thus a reversible process.

While for a non-quasi equilibrium process, it takes more work to move the piston against this high-pressure region.

5 0
3 years ago
Read 2 more answers
The hot and cold inlet temperatures to a concentric tube heat exchanger are Th,i = 200°C, Tc,i = 100°C, respectively. The outlet
alexgriva [62]

Answer:Counter,

0.799,

1.921

Explanation:

Given data

T_{h_i}=200^{\circ}C

T_{h_o}=120^{\circ}C

T_{c_i}=100^{\circ}C

T_{c_o}=125^{\circ}C

Since outlet temperature of cold liquid is greater than hot fluid outlet temperature therefore it is counter flow heat exchanger

Equating Heat exchange

m_hc_{ph}\left [ T_{h_i}-T_{h_o}\right ]=m_cc_{pc}\left [ T_{c_o}-T_{c_i}\right ]

\frac{m_hc_{ph}}{m_cc_{pc}}=\frac{125-100}{200-120}=\frac{25}{80}=C\left ( capacity rate ratio\right )

we can see that heat capacity of hot fluid is minimum

Also from energy balance

Q=UA\Delta T_m=\left ( mc_p\right )_{h}\left ( T_{h_i}-T_{h_o}\right )

NTU=\frac{UA}{\left ( mc_p\right )_{h}}=\frac{\left ( T_{h_i}-T_{h_o}\right )}{T_m}

T_m=\frac{\left ( 200-125\right )-\left ( 120-100\right )}{\ln \frac{75}{20}}

T_m=41.63^{\circ}C

NTU=1.921

And\ effectiveness \epsilon =\frac{1-exp\left ( -NTU\left ( 1-c\right )\right )}{1-c\left ( -NTU\left ( 1-c\right )\right )}

\epsilon =\frac{1-exp\left ( -1.921\left ( 1-0.3125\right )\right )}{1-0.3125exp\left ( -1.921\left ( 1-0.3125\right )\right )}

\epsilon =\frac{1-exp\left ( -1.32068\right )}{1-0.3125exp\left ( -1.32068\right )}

\epsilon =\frac{1-0.2669}{1-0.0834}

\epsilon =0.799

5 0
4 years ago
If the density of states function in the conduction band of a particular semiconductor is a constant equal to K, derive the expr
s2008m [1.1K]

Answer:

full details of the answer is attached

5 0
3 years ago
Which of the following is the last step in creating a budget?
Greeley [361]

Answer:

<em>D. Determine saving or debt</em>

Explanation:

7 0
3 years ago
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