Answer:
Correct sentence: (c) more.
Explanation:
Otto cycle:
An ideal Otto cycle models the behavior of an explosion engine. This cycle consists of six steps, as indicated in the figure. Prove that the performance of this cycle is given by the expression
η = 1 - (1/r^(ρ-1))
where r = VA / VB is the compression ratio equal to the ratio between the volume at the beginning of the compression cycle and at the end of it. ρ=1.4
Diesel cycle:
The ideal Diesel cycle is distinguished from the ideal Otto in the combustion phase, which in the Otto cycle is assumed at a constant volume and in the Diesel at constant pressure. Therefore the performance is different.
If we write the performance of a Diesel cycle in the form
:
η = 1 - (1/r^(ρ-1)) × ( (r^ρ)-1)/(ρ^(r-1)) )
we see that the efficiency of a Diesel cycle differs from that of an Otto cycle by the factor in parentheses. This factor is always greater than the unit, therefore, for the same compression reasons r
diesel performance is less than otto performance
\ eta_ \ mathrm {Diesel} <\ eta_ \ mathrm {Otto} \,
Answer:
C . . . . . . . . . . . . . . . . . . . . . .
Before calculating the volume of this cylinder, we must either convert the diameter to feet or the height to inches. I'll do the latter, to avoid getting a very small number.
Recall that there are
12
inches in
1
foot. Thus, we can state:
12
in.
1
ft.
=
x
4
ft.
x
=
12
in.
×
4
ft.
1
(ft.)
x
=
48
in.
Hence, the cylinder has a height of
48
inches.
Now, we can apply the formula for volume of a cylinder to effectuate our calculation. The formula in question is
V
=
a
base
×
h
, or
V
=
r
2
π
×
h
.
However, we know our diameter but we don't know our radius. As you probably know, the diameter is linked to the radius b the formula
d
=
2
r
. Solving for
r
and substituting:
r
=
d
2
r
=
12
2
r
=
6
∴
The radius of the cylinder measures
6
inches.
V
=
r
2
π
×
h
V
=
6
2
π
×
48
V
=
(
36
×
48
)
π
V
=
1728
π
in
2
Note that this answer is in exact value. Rounded to two decimal places, the volume is
5428.67
in
Answer:
lol i thought that said carrot engine. But i actually put some study into this but couldn't find this answer sorry
Explanation:
Answer:
The program is as follows:
i = 1
while(i<11):
j = 1
while(j<=i):
print('*', end = '')
j += 1
i += 1
print()
Explanation:
Initialize i to 1
i = 1
The outer loop is repeated as long as i is less than 11
while(i<11):
Initialize j to 1
j = 1
The inner loop is repeated as long as j is less than or equal i
while(j<=i):
This prints a *
print('*', end = '')
This increments j and ends the inner loop
j += 1
This increments i
i += 1
This prints a blank and ends the inner loop
print()
