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andrezito [222]
3 years ago
11

Graph the image of the given segment under a di6with scale factor -1/3 and center of dilatation (0,0). Line on graph is A (-6,9)

B (-3,3) please explain to me how I solve this.

Mathematics
1 answer:
pav-90 [236]3 years ago
5 0

Answer:

A ' = (2, -3)

B ' = (1, -1)

See attached image below for the diagram

========================================================

Explanation:

Point A is originally at (-6, 9). It moves to A ' (2,-3) after applying the scale factor. This is because we basically multiply the scale factor (-1/3) by each coordinate of point A

-6 * (-1/3) = 2

9 * (-1/3) = -3

The negative scale factor is like a mirror in a way. Points in negative regions move to positive regions, and vice versa. Since |-1/3| = 1/3 is less than 1, this means the new point (2,-3) is closer to (0,0) compared to its original counterpart.

Point B follows the same idea

B(-3,3) moves to B ' (1, -1) after multiplying each coordinate by -1/3

-------------

Side note: The segment A'B' is 1/3 as long compared to segment AB.

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nataly862011 [7]
A.
-1: 
2(2)^{-1}  \\ 2( \frac{1}{2}) \\  \frac{2}{2}  \\ 1
(-1,1)

0:
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1:
2(2)^{1}  \\ 2(2) \\ 4
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b.
To graph the equation, simply go through the points (-2, 0.5), (-1, 1), (0,2), (1,4), (2,8), and (3,16). Make sure you never go below 0 on the x-axis, because there's an asymptote there.

Hope this helps!
8 0
3 years ago
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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

y=kx+1

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