Graph the image of the given segment under a di6with scale factor -1/3 and center of dilatation (0,0). Line on graph is A (-6,9)
B (-3,3) please explain to me how I solve this.
1 answer:
Answer:
A ' = (2, -3)
B ' = (1, -1)
See attached image below for the diagram
========================================================
Explanation:
Point A is originally at (-6, 9). It moves to A ' (2,-3) after applying the scale factor. This is because we basically multiply the scale factor (-1/3) by each coordinate of point A
-6 * (-1/3) = 2
9 * (-1/3) = -3
The negative scale factor is like a mirror in a way. Points in negative regions move to positive regions, and vice versa. Since |-1/3| = 1/3 is less than 1, this means the new point (2,-3) is closer to (0,0) compared to its original counterpart.
Point B follows the same idea
B(-3,3) moves to B ' (1, -1) after multiplying each coordinate by -1/3
-------------
Side note: The segment A'B' is 1/3 as long compared to segment AB.
You might be interested in
above is the distance formula, plugging your numbers from P(x1,y1) and Q(x2,y2).
or