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castortr0y [4]
2 years ago
11

A television company charges $60 for the first half-hour of work and $40 for each additional hour. Blue mountain camp has budget

ed $200 to repair its collection of televisions. For what lengths of a service call will the budget not exceed?
Mathematics
1 answer:
Alexandra [31]2 years ago
4 0

Answer:

For a length of total of  4 hrs,  the budget of $200  will not exceed.

Step-by-step explanation:

Here, the first half hour charge for repairing = $60

The next hour charge  = $40 her hour

Total budget to be spent  by Blue Mountain Camp = $200

Now, here, the cost of 0.5 hour  = $60

So, the amount left after 0.5 hour repair  = $200 - $60 = $140

Let us assume we can hire the service for m hours in $140

Cost of 1 hour charge  = $40

Cost of m hour charge  = m X ( 1 hour charge) = m x ($40) = 40 m

⇒ 40 m = 140

or, m= 140/40 = 3.5, or m = 3.5

⇒ In $140 left, they can get a service of 3.5 hours at $40 per hour.

Now, the total hours of services hired = 0.5 hour in $60 + 3.5 hr in $140

= 0.5 hr + 3.5 hr = 4 hrs

Hence, for a length of total of  4 hrs, the budget of $200  will not exceed.

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