Plug in 35 into the equation P(t)
P(35) = 14(35)^2+650(35)+32,000
The area would be 35 cm squared.
Lets break it down:
Triangle- The area of a triangle is base×height÷2
so if we plug in the numbers, the base would be 5 (the length) and the height would be 4 (the height). 5×4= 20÷2= 10.
Square- The area of a square is base×height so if we pluged in the numbers, the base is 5 (the length) and the height is 5 (the height). 5×5= 25.
10+25= 35 cm squared
Hope this helps!
Answer:
The areas of the squares adjacent to two sides of a right triangle are shown below.
What is the area of the square adjacent to the third side of the triangle?
units^2
2
Step-by-step explanation:
V = (4/3)π.R³
Diameter - 24 units so Radius = 24/2 = 12 Inits
V= (4π/3).12³ =(4π/3). 1728
V=1728 x 4/3 x π = 2,304.π units³
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