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Anit [1.1K]
3 years ago
14

t takes Franklin 14 hours to make a 200-square-foot cement patio. It takes Scott 10 hours to make the same size patio. Which equ

ation can be used to find x, the number of hours it would take Franklin and Scott to make the patio together?
Mathematics
1 answer:
Tasya [4]3 years ago
7 0
The efficiency of Franklin: 200/14 ft^2/hr

Scott: 200/10 ft^2/hr

So together: 200 / (200/14 + 200/10) = 5.83 hours
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It took a submarine 30 seconds to sink 225 feet, moving at a constant speed. The captain wants to know the submarine's speed.
Vladimir [108]

Answer:

Speed per second= 7.5 feet per second

Step-by-step explanation:

Giving the following information:

We have a distance (225 feet), and a time (30 seconds). Also, we know that the speed was constant.

<u>All we have to do is divide the distance by the time and determine the speed per second:</u>

Speed per second= distance / time

Speed per second= 225 / 30

Speed per second= 7.5 feet per second

5 0
3 years ago
The table shows the different packs of sports cards available for purchase. What is the smallest number of baseball and football
WARRIOR [948]
<span>The least common multiple would be 280 cards of each. 

20 Packs of football, 8 packs of Hockey, and 7 packs of Baseball.</span>
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Answer:

The temperature needs to rise <u>1.5</u> degree C to reach 0 degree C.

Step-by-step explanation:

-1.5+<u>1.5</u>=0

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Simplify: 3m over m-6 •5m3 - 30m2 over 5m2
vfiekz [6]
\frac{3(5m^{4}-2m +12)}{m-6} should be the right answer
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3 years ago
Find the indefinite integral using the substitution provided.
Nady [450]

Answer:  7\text{Ln}\left(e^{2x}+10\right)+C

This is the same as writing 7*Ln( e^(2x) + 10) + C

=======================================================

Explanation:

Start with the equation u = e^{2x}+10

Apply the derivative and multiply both sides by 7 like so

u = e^{2x}+10\\\\\frac{du}{dx} = 2e^{2x}\\\\7\frac{du}{dx} = 7*2e^{2x}\\\\7\frac{du}{dx} = 14e^{2x}\\\\7du = 14e^{2x}dx\\\\

The "multiply both sides by 7" operation was done to turn the 2e^(2x) into 14e^(2x)

This way we can do the following substitutions:

\displaystyle \int \frac{14e^{2x}}{e^{2x}+10}dx\\\\\\\displaystyle \int \frac{1}{e^{2x}+10}14e^{2x}dx\\\\\\\displaystyle \int \frac{1}{u}7du\\\\\\\displaystyle 7\int \frac{1}{u}du\\\\\\

Integrating leads to

\displaystyle 7\int \frac{1}{u}du\\\\\\7\text{Ln}\left(u\right)+C\\\\\\7\text{Ln}\left(e^{2x}+10\right)+C\\\\\\

Be sure to replace 'u' with e^(2x)+10 since it's likely your teacher wants a function in terms of x. Also, do not forget to have the plus C at the end. This is a common mistake many students forget to do.

To verify the answer, you can apply the derivative to it and you should get back to the original integrand of \frac{14e^{2x}}{e^{2x}+10}

4 0
2 years ago
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