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2 years ago

Calculate 50% of 684 m. Give your answer in metres (m).

Mathematics

2 answers:

Phantasy [73]2 years ago

4 0

Answer:

Step-by-step explanation:

Calculate 50% of 684 m.

Give your answer in metres (m).

50% = 1/2

684 : 2 = 342 m

Naily [24]2 years ago

4 0

Step-by-step explanation:

50% of 684

50/100 × 684

342m ans

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3 years ago

Carmela randomly selected 85 stamps from a stamp collection. Eleven of these were commemorative stamps.

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Answer:

(0.095, 0.165)

Step-by-step explanation:

Confidence interval :

Phat ± margin of error

Margin of Error = 0.035

Phat = x / n

Phat = 11 / 85 = 0.1294117

Hence,

Phat ± 0.035

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3 years ago

The correct factorization of 12x'2 - 157x - 40: A) (3x -8)(4x - 5) B) (3x - 40)(4x + 1) C) (12x - 1)(x + 40) D) (12x - 5)(x-8)

irinina [24]

Answer:

Step-by-step explanation:

12x² - 157x - 40

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term

product = 12 × - 40 = - 480 and sum = - 157

The factors are + 3 and - 160

Use these factors to split the x- term

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3 years ago

A woman is emptying her aquarium at a steady rate with a small pump. The water pumped to a 12-in.-diameter cylindrical bucket, a

Temka [501]

Answer:

Therefore the rate at which water level is dropping is $\frac{11}{21}$ in per minute.

Step-by-step explanation:

Given that,

The diameter of cylindrical bucket = 12 in.

Depth is increasing at the rate of = 4.0 in per minutes.

i.e $\frac{dh_1}{dt}=4$

$h_1$ is depth of the bucket.

The volume of the bucket is V = $\pi r^2 h$

$=\pi \times 6^2\itimes h_1$

$\therefore V=36\pi h_1$

Differentiating with respect yo t,

$\frac{dV}{dt}=36\pi \frac{dh_1}{dt}$

Putting $\frac{dh_1}{dt}=4$

$\therefore\frac{dV}{dt}=36\pi\times 4$

The rate of volume change of the bucket = The rate of volume change of the aquarium .

Given that,The aquarium measures 24 in × 36 in × 18 in.

When the water pumped out from the aquarium, the depth of the aquarium only changed.

Consider h be height of the aquarium.

The volume of the aquarium is V= ( 24× 36 ×h)

V= 24× 36 ×h

Differentiating with respect to t

$\frac{dV}{dt}=24\times 36 \times \frac{dh}{dt}$

Putting $\frac{dV}{dt}=36\pi\times 4$

$36\pi\times 4= 24\times 36\times \frac{dh}{dt}$

$\Rightarrow \frac{dh}{dt}=\frac{36\pi \times 4}{24\times 36}$

$\Rightarrow \frac{dh}{dt}=\frac{11}{21}$

Therefore the rate at which water level is dropping is $\frac{11}{21}$ in per minute.

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3 years ago