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3 years ago

the constant value which is repeatedly added to each term in an arithmetic sequence to obtain the next term

Mathematics

1 answer:

Mariulka [41]3 years ago

7 0

Answer:

<h2>This value is called the common difference</h2>

Step-by-step explanation:

The common difference is the constant value which is repeatedly added to each term in an arithmetic sequence to obtain the next term, it is basically the difference between consecutive numbers

To find the common difference we can subtract the previous term from the first time or the second to the last term from the last term, the idea of finding the common difference is basically subtracting the previous term form the subsequent term.

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Solve the equation -4(3x+2)=88

Goshia [24]

Answer:

x=-8

Step-by-step explanation:

first do whats in the parenthess and it will look like this

-12x-8=88 now add 8 to 88 and you get 96

-12x=96 now you want x by itself so divide -12 into 96 and you get -8

x=-8

4 0

3 years ago

I really don't understand how roots work with these. Please help

zheka24 [161]

Answer: This is geometry. Put point C at (-4,-3). Distance from A to C = AC = 5. Distance from C to B = CB = 9. Then ACB is a right triangle with legs AC and CB, and hypotenuse AB, so

AC^2 + CB^2 = AB^2, so

AB = √(AC^2 + CB^2) = √(5^2+9^2) = √(25+81) = √106.

However, in vector algebra, A=(-4,3) and B=(5,-2), and (A-B)=(-9,5).

distance(A,B) = √((A-B) dot (A-B)),

where (x,y) dot (x,y) = x×x + y×y.

So the answer is √((-9,5)dot(-9,5)) = √((-9)^2+5^2) = √(81+25) = √106.

This works in 3D, (x,y,z) dot (x,y,z) = x×x + y×y + z×z. distance(A,B) gives √(x^2+y^2+z^2) for distances in 3 dimensions.

In 4D, distance is √(x^2+y^2+z^2+w^2)

And in infinite dimensional Hilbert space, (x,y,z,a,b,c,...) dot (x,y,z,a,b,c,...) = x×x + ... c×c + .... distance(A,B) gives

√(x^2+...+c^2+...).

And for real valued functions, f(x) dot g(x) is roughly the sum of f(x)×g(x) over uncountably many points x from -infinity to +infinity. It's the area under h(x)=f(x)g(x).

8 0

3 years ago

How far can the center of the box be from the end of the table before the board begins to tilt?

Vesnalui [34]

in case of box start being tilt,

box should be half out the table,

The Center of Mass of an object or system of objects is a location that is specified in relation to those objects. The Center of Mass of a system is the location where all of its components are on average when they are all weighted in accordance with their masses. The centroid is where basic stiff objects with homogenous density have their centers of mass. Sometimes an object's Center of Mass might not be directly over it. The Center of Mass would be on the Center in the event of a uniform disc, but there would be no material in the case of a ring where the Center of Mass would be on the Center.

The Centre of Mass for intrinsic shapes can be defined as the position where the sum of all of its weighted position vectors of all the parts equals zero.

In this we can use the Center of Mass concept,

As it will leave table when normal is not acting from the table at the center of mass.

So, as in case of box measuring ( x, y, z ) the center of mass from any point of the box is $\sqrt{x^{2} +y^{2}+ z^{2} }$

So in case of box start being tilt,

box should be half out the table,

So that COM must be just outside the table

To learn more about Position vector , visit,

brainly.com/question/1563531

#SPJ1

7 0

1 year ago

7th grade math help me please :)))

yanalaym [24]

Answer:

$284.99 should go to Mr. Aceves’ class, $174.41 should go to Mrs. Baca’s class, and $140.60 should go to Mr. Canyon’s class.

Step-by-step explanation:

Firstly, to calculate the portions each class should have, we should find the proportion each class takes up.

Hence, let's say A represents Mr. Aceves' class, B represents Mrs. Baca's class, and C represents Mr. Canyon's class.

The total number of box tops collected would be 3760 + 2301 + 1855 = 7916 box tops.

Therefore, the total proportions would be:

A = $\frac{3760}{7916}$

B = $\frac{2301}{7916}$

C = $\frac{1855}{7916}$

Hence, we can finally multiply these proportions with the total prize to find the appropriate division:

Mr. Aceves' class gets $\frac{3760}{7916} \cdot 600 \approx 284.99$ .

Mrs. Baca's class gets $\frac{2301}{7916} \cdot 600 \approx 174.41$ .

And Mr. Canyon's class gets $\frac{1855}{7916} \cdot 600 \approx 140.60$ .

Finally, $284.99 should go to Mr. Aceves’ class, $174.41 should go to Mrs. Baca’s class, and $140.60 should go to Mr. Canyon’s class.

Hope this helped!

7 0

2 years ago

Michael earned $159 mowing lawns all summer. If he mowed 39 lawns, about how much did he make per lawn?

monitta

Divide 159 by 39 to get around $4.08

4 0

3 years ago

the constant value which is repeatedly added to each term in an arithmetic sequence to obtain the next term​

the constant value which is repeatedly added to each term in an arithmetic sequence to obtain the next term