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mixas84 [53]
3 years ago
8

A recent study was conducted to determine the concentration of lead in drinking water across various states. 25 water samples fr

om the state of Washington were tested; the mean lead concentration was found to be 0.15%. This compares to 32 water samples in the state of Minnesota where the mean was reported to be 0.21%. The data was calculated to be significant at the 0.0001 level. Determine the meaning of this significance level.
Mathematics
1 answer:
Nataliya [291]3 years ago
8 0

Answer:

When is at a significance level of 0.0001, the concentration of lead is above in water from Minnesota.

Step-by-step explanation:

The Significance level is the calculation or estimation of the strength of proof that must be seen in a sample, before the hypothesis will be rejected and concluded that the result is statistically true or correct.

In this case, when a data is calculated to be significant at 0.0001 from a recent duty, what the significance level implies in this case is that, at  a level of 0.001, the concentration of lead is above or higher in water from Minnesota.

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What is 7 8/13 rounded to the nearest whole number?
vfiekz [6]

Answer: The answer would be 8.

Step-by-step explanation: I'm going to assume you mean 7 8/13 is a mixed fraction. So you multiply the denominator, 13, multiply 7 to that, then add 8 to it and the denominator would be the same as before. That should give you 99/13. When you divide, you get around 7.6, rounding closest to 8.  

6 0
2 years ago
Ou have found a house that you would like to purchase. The amount of the home is $225,000. You would like to finance the home th
Tpy6a [65]

Answer:

  A.  $22,500

Step-by-step explanation:

10% = 10/100 = 1/10

To divide a decimal number by 10, move the decimal point one place to the left (remove a zero):

  $225000./10 = $22500.0 = $22500

5 0
3 years ago
X: 2,4,6,8,10
Morgarella [4.7K]

~Hello There!~

12/2 = 6

24/4 = 6

36/6 = 6

etc.

As you can see, y is always 6 times the value of x.

Therefore, the equation would be y = 6x

Hope This Helps You!

Good Luck :)

Have A Great Day ^_^

- Hannah ❤

8 0
3 years ago
In order to ensure efficient usage of a server, it is necessary to estimate the mean number
juin [17]

Answer:

a. [36.19;39.21]

b. Reject the null hypothesis. The population mean of users that are connected at the same time is greater than 35.

Step-by-step explanation:

Hello!

Your study variable is,

X: "number of users of one server at a time"

The objective is to estimate the mean, for this, a sample of n=100 times was taken and the standard deviation S= 9.2 and the sample mean is X[bar]= 37.7 were calculated.

You need to study the population mean, for this you need your variable to have at least normal distribution. Since you don't have information about its distribution, but the sample is big enough (n≥30) you can apply the Central Limit Theorem and approximate the distribution of the sample mean X[bar] to normal:

X[bar]≈N(μ;σ²/n)

a. With this approximation, you can construct the 90% Confidence Interval using the approximate Z

[X[bar] ± Z_{1-\alpha /2} * S/√n]

Z_{1-\alpha /2} = Z_{0.95} = 1.64

[37.7± 1.64* 9.2/√100]

[36.19;39.21]

b. You need to test if the population mean is greater than 35 with a level of significance of 1%.

The hypothesis is:

H₀: μ ≤ 35

H₁: μ > 35

α: 0.01

This is a one-tailed test so you have only one critical level (right tail):

Z_{1\alpha } = Z_{0.99} = 2.33

This means that if the value of the calculated statistic is equal or greater than 2.33 you will reject the null Hypothesis.

If the value is less than 2.33 you will support the null hypothesis.

The statistic is:

Z=<u> X[bar] - μ </u>= <u> 37.7 - 35 </u> = 2.93

       S/√n           9.2/10

The value 2.93 > 2.33, so you reject the null hypothesis. This means that the population mean of users that are connected at the same time is greater than 35.

<u><em>Note: </em></u><em>To make the decision using the interval calculated on a), the hypothesis should have been two-tailed and the confidence and significance levels complementary.</em>

I hope it helps!

7 0
2 years ago
Suppose the man in the St. Ives poem has x wives, each wife has x sacks, each sack has x cats, and each cat has x kits. Write an
Harrizon [31]

Answer:

x^{1} wives

x^{2} sacks

x^{3} cats

x^{4} kits

Suppose the man in the St. Ives poem has x wives, each wife has x sacks, each sack has x cats, and each cat has x kits. Write an expression using exponents that represents the total number of kits, cats, sacks, and wives going to St .Ives.

Step-by-step explanation:

x^{1} wives

If each of the "x" wives has "x" sacks, so the number of sacks is:

x^{2} sacks

If each of the "x" wives has "x" sacks, and each sack has "x" cats, so the number of cats is:

x^{3} cats

If each of the "x" wives has "x" sacks, and each sack has "x" cats, and each cat has "x" kits, so the number of kits is:

x^{4} kits

8 0
2 years ago
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