Matrices always go row x column.
Count the rows: 4
Count the columns: 3
The matrix is a 4 x 3 matrix
Yes, they can be added and simplified further. 2√3 + 5√3 = 7√3 .
Take √3 as common factor:
2√3 + 5√3
(2 + 5)√3
7√3
The two irrational numbers sums to form another irrational number 7√3 . In decimals that is 12.12435...
Answer:
The correct option is;
a) It moves five places to the right
Step-by-step explanation:
Multiplying a whole number by 10 raised to a given (positive whole number) power, involves the shifting of the positioning of the decimal places to the right, depending on the value of the positive whole number power to which the 10 is raised
Similarly, multiplying a whole number by 10 raised to a given (negative whole number) power, involves the shifting of the positioning of the decimal places to the left, depending on the value of the negative whole number power to which the 10 is raised.
The reason is because, the number base generally used for arithmetic is in base 10 and multiplying or dividing by 10 is what is required to change a number's place value
Therefore, multiplying a whole number by 10 raised to the 5th power (10⁵) requires shifting the decimal place 5 places to the right
Example:
x.0 × 10⁵ = x00000.0
Where, x is a whole number.
50 adult tickets and 20 children tickets were sold for the concert.
Step-by-step explanation:
Given,
Number of concert tickets sold = 70
Revenue generated = $550
Cost of each adult ticket = $9
Cost of each child ticket = $5
Let,
x be the number of adult tickets sold
y be the number of child tickets sold
According to given statement;
x+y=70 Eqn 1
9x+5y=550 Eqn 2
Multiplying Eqn 1 by 5
Subtracting Eqn 3 from Eqn 2
Dividing both sides by 4
Putting x=50 in Eqn 1
50 adult tickets and 20 children tickets were sold for the concert.
Keywords: linear equation, elimination method
Learn more about linear equations at:
#LearnwithBrainly
1) Dimensiones of the cardboard:
length: 10 inches
width: 8 inches
2) dimensions of the squares cut
length: x
width: x
3) dimensions of the box:
length of the base = 10 - 2x
width of the base = 8 - 2x
height = x
4) Volume of the box
V = (10 - 2x) (8 - 2x) x = x [80 - 20x - 16x + 4x^2] = x [ 80 - 36x + 4x^2 ] =
V = 80x - 36x^2 + 4x^3
5) Maximum volume => derivative of V, V' = 0
V' = 80 - 72x + 12x^2 = 0
6) Solve the equation
Divide by 4 => 3x^2 - 18x + 20 = 0
Use the quadratic formula: x = 1.47 and x = 4.53 (this is not valid)
So, the answer is the option C. 1.5 inches.
