F(x)=x^3-9x
and
g(x)=x^2-2x-3
so you just need to divide f(x) by g(x)
Therefore:
f(x)/g(x) = (x^3-9x) / (x^2-2x-3)
and of course you need to factor these two function to see if some factor would cancel another
x^3-9x = x(x^2-9)=x(x-3)(x+3)
and
x^2-2x-3 = (x-3)(x+1)
X=2.5 the triangles are 2x the scale of the other one so if you divide the numbers on the triangle by 2 then you will get the answer for x
Answer:
Step-by-step explanation: This is the answer
Answer:
- 508
Step-by-step explanation:
The n th term of an arithmetic sequence is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = - 28 and d = - 34 - (- 28) = - 34 + 28 = - 6, thus
= - 28 + (- 6 × 80) = - 28 - 480 = - 508
18x^5-3x^4+x^3-x^2-72x^3+12x^2-4x+4, and then you will combine like terms to be :
18x^5-3x^4-71x^3+11x^2-4x+4
