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a_sh-v [17]
3 years ago
11

Which describes of a portion or share of ownership in a corporation?

Mathematics
2 answers:
Mkey [24]3 years ago
7 0

Answer:

C. Stock.

Step-by-step explanation:

ira [324]3 years ago
3 0
If I can remember correctly I think it is C: stocks
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Suppose you are putting up a tent for a camping trip.
SSSSS [86.1K]

The length of the rope needed is 15 feet

Given the following parameters;

  • Height of the pole = 9 foot
  • The distance from the <u>rope away from the base </u>of the pole is 12 feet

Required

  • Length of the rope.

To get the length of the rope, you will use the pythagoras theorem expressed as:

  • c² = a² + b²

Substituting the given parameters:

c² = 9² + 12²

c² =81 + 144

c² = 225

c = √225

c = 15 feet

Therefore the length of the rope needed is 15 feet

Learn more on Pythagoras theorem here: brainly.com/question/231802

7 0
2 years ago
Im confused, can someone help?
Bumek [7]
Well, the y-intercept is represented by B. So b would be the dot crossing the y-axis in each graph (which you already circled). Next, the slope for top left is: -1.5, top right is: -1.7, bottom left is: 3, and bottom right is: 1.33. I got those by using this very helpful website named Desmos. Now, I’m order to write the equation for each graph is very simple, all you have to do is put in the slope and y-intercept into the equation. For example, the top left one would be:
y = -1.5x + 4 since we know that the slope is equal to -1.5 and the y-intercept is equal to 4. Hope this helps :)
8 0
3 years ago
Calculate the specific heat of a metal (in calories/gram-degree C) from the following data. A container made of the metal has a
Arisa [49]

Answer:

<h2>The specific heat of the metal is 0.274951 calories/gram-degree C.</h2>

Step-by-step explanation:

Let, the specific heat of the container is x calories/gram-degree C.

The container and water gains (18 - 15) = 3 degrees C.

Hence, the transfer of heat is 3(18.1\times1000\times1) + 3(3.77x\times1000).

The metal, which is dropped in the water, losses (164 - 18)= 144 degrees C.

Hence, the transfer of heat is 144\times 1.45\times1000x.

As per the given conditions,

3(18.1\times1000) + 3(3.77x\times1000) = 144\times1.45\times1000x\\54.3 + 11.31x = 208.8x\\197.49x = 54.3\\x = 0.274951.

6 0
3 years ago
Find the point(s) on the surface z^2 = xy 1 which are closest to the point (7, 11, 0)
leonid [27]
Let P=(x,y,z) be an arbitrary point on the surface. The distance between P and the given point (7,11,0) is given by the function

d(x,y,z)=\sqrt{(x-7)^2+(y-11)^2+z^2}

Note that f(x) and f(x)^2 attain their extrema, if they have any, at the same values of x. This allows us to consider the modified distance function,

d^*(x,y,z)=(x-7)^2+(y-11)^2+z^2

So now you're minimizing d^*(x,y,z) subject to the constraint z^2=xy. This is a perfect candidate for applying the method of Lagrange multipliers.

The Lagrangian in this case would be

\mathcal L(x,y,z,\lambda)=d^*(x,y,z)+\lambda(z^2-xy)

which has partial derivatives

\begin{cases}\dfrac{\mathrm d\mathcal L}{\mathrm dx}=2(x-7)-\lambda y\\\\\dfrac{\mathrm d\mathcal L}{\mathrm dy}=2(y-11)-\lambda x\\\\\dfrac{\mathrm d\mathcal L}{\mathrm dz}=2z+2\lambda z\\\\\dfrac{\mathrm d\mathcal L}{\mathrm d\lambda}=z^2-xy\end{cases}

Setting all four equation equal to 0, you find from the third equation that either z=0 or \lambda=-1. In the first case, you arrive at a possible critical point of (0,0,0). In the second, plugging \lambda=-1 into the first two equations gives

\begin{cases}2(x-7)+y=0\\2(y-11)+x=0\end{cases}\implies\begin{cases}2x+y=14\\x+2y=22\end{cases}\implies x=2,y=10

and plugging these into the last equation gives

z^2=20\implies z=\pm\sqrt{20}=\pm2\sqrt5

So you have three potential points to check: (0,0,0), (2,10,2\sqrt5), and (2,10,-2\sqrt5). Evaluating either distance function (I use d^*), you find that

d^*(0,0,0)=170
d^*(2,10,2\sqrt5)=46
d^*(2,10,-2\sqrt5)=46

So the two points on the surface z^2=xy closest to the point (7,11,0) are (2,10,\pm2\sqrt5).
5 0
3 years ago
Two brothers went shopping at a back to school sale where all shirts and shorts were the same price. The younger brother spent $
hjlf

Answer:

10 dollars

Step-by-step explanation:

Hope this helped :D

5 0
3 years ago
Read 2 more answers
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