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babymother [125]
3 years ago
15

Three consecutive integers have a sum of 114. what are the three integers

Mathematics
2 answers:
Anuta_ua [19.1K]3 years ago
8 0
Let the smallest one be x, the second one is then x+1, the third one is x+2
x+(x+1)+(x+2)=114
3x+3=114
3x=111
x=37
the three consecutive integers are: 37,38,39
Mandarinka [93]3 years ago
7 0

Our three consecutive integers are 37, 38, and 39.

Work is provided in the image attached.

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What is the length of the cylinder's height? Please help​
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Answer:

  • Height = <u>9</u><u> </u>cm which means <u>Option </u><u>C </u>is the answer

Step-by-step explanation:

In the question we are given ,

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And , we have to find the <u>height</u><u> of</u><u> </u><u>cylinder</u><u> </u>.

We know that ,

\longrightarrow \pink{ \boxed{Volume \:  of \:  Cylinder = \pi r {}^{2}h  }} \longleftarrow

Our solution starts from here :

\longmapsto \: \pi \: r {}^{2} h = 225\pi

<u>Step </u><u>1</u><u> </u><u>:</u> Cancelling π with π :

\longmapsto \:  \cancel{\pi} \: r {}^{2} h = 225 \cancel{\pi}

<u>Step </u><u>2</u><u> </u><u>:</u> Substituting value of radius which is 5 cm in the formula :

\longmapsto \: (5) {}^{2}  \times h = 225

\longmapsto \: 25h = 225

<u>Step </u><u>3 </u><u>:</u> Transposing 25 to right hand side :

\longmapsto \: h =  \frac{225}{25}

<u>Step </u><u>4</u><u> </u><u>:</u> Cancelling 225 by 25 :

\longmapsto \:   \red{\boxed{h = 9 \: cm}}

  • <u>Henceforth</u><u> </u><u>,</u><u> </u><u>height</u><u> </u><u>of </u><u>cylinder</u><u> is</u><u> </u><u>9</u><u> </u><u>cm</u>

<h2 /><h2><u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>
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2 years ago
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<em>Hey</em><em>!</em><em>!</em><em>!</em><em>!</em>

<em>Here</em><em>'s</em><em> </em><em>you</em><em>r</em><em> </em><em>answer</em><em>:</em>

<em>Sol</em><em>ution</em><em>:</em>

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<em>B</em><em>=</em><em>{</em><em>5</em><em>,</em><em>6</em><em>,</em><em>7</em><em>,</em><em>8</em><em>}</em>

<em> </em><em>A</em><em> </em><em>U</em><em> </em><em>B</em><em>=</em><em>{</em><em>2</em><em>,</em><em>3</em><em>,</em><em>4</em><em>,</em><em>5</em><em>}</em><em> </em><em>U</em><em> </em><em>{</em><em>5</em><em>,</em><em>6</em><em>,</em><em>7</em><em>,</em><em>8</em><em>}</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>{</em><em>2</em><em>,</em><em>3</em><em>,</em><em>4</em><em>,</em><em>5</em><em>,</em><em>6</em><em>,</em><em>7</em><em>,</em><em>8</em><em>}</em>

<em>In</em><em> </em><em>case</em><em> </em><em>of</em><em> </em><em>Union</em><em>,</em><em>we</em><em> </em><em>have</em><em> </em><em>to</em><em> </em><em>list</em><em> </em><em>all</em><em> </em><em>the</em><em> </em><em>elements</em><em> </em><em>which</em><em> </em><em>are</em><em> </em><em>present</em><em> </em><em>in</em><em> </em><em>both</em><em> </em><em>sets</em><em>.</em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps.</em><em>.</em><em>.</em>

<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>

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3 years ago
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