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Vikki [24]
3 years ago
12

What is the answer and formula for 7f+5=68

Mathematics
1 answer:
gladu [14]3 years ago
4 0
7f=68-5
7f=63
f=63/7
f=9
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Can someone help me with my homework...? Its about graphing functions and tables, I'll post it right now! But can someone who kn
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Answer:

sure where is the attachment?

Step-by-step explanation:

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2 years ago
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One number is 3 times a first number. A third number is 100 more than the first number. If the sum of the three numbers is 510,
Brums [2.3K]

Answer:

82

Step-by-step explanation:

solve a + (3a) + (a + 100)=510

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3 years ago
What is the rate of change of the function y = − 1/4 x + 1
scoray [572]

Answer:

-1/4

Step-by-step explanation:

Hello!

The rate of change is also known as the slope.

Standard equation of a line: y = mx + b

  • y: output
  • m:  slope
  • x: input
  • b: y-intercept

So, if we match the standard form to the given function:

  • y = mx + b
  • y = -1/4x + 1

-1/4 is m, or the rate of change.

8 0
2 years ago
Write four different expressions for the perimeter of a pentagon whose sides are all s-2 units long?
Masteriza [31]

Hey there!

1. 5(s-2) This is because s-2 is the length of each side, and there are 5 sides in a pentagon all of that length, so multiplying it by 5 like this shows its perimeter.

2. 5s-10 This can be found by distributing the first equation, multiplying both s and -2 by 5.

3. (s-2) + (s-2) + (s-2) + (s-2) + (s-2) Each grouping in the parenthesis represents each of the 5 sides, so adding them all together will get you the perimeter.

4. 5(s) + 5(-2) This one is most like the first one, except it's a little more spread out. Multiply the term s by the 5 sides in one grouping, and the integer -2 by 5 in the other.

Hope this helps!

4 0
2 years ago
A tank contains 90 kg of salt and 1000 L of water. A solution of a concentration 0.045 kg of salt per liter enters a tank at the
Andreyy89

Answer:

Step-by-step explanation:

concentration = amount of salt/solution

A) Initial concentration= 90/1000 = 0.09

Q = quantity of salt

Q(0) = 90 kg

Inflow rate = 8 l/min

Outflow rate = 8 l/min

Solution = 1000 L at any time t.

Salt inflow = 0.045 * 8 per minute

= 0.36 kg per minute

This is mixed and drains from the tank.

Outflow = \frac{Q(t)}{1000}

Thus rate of change of salt

Q'(t) = inflow - outflow = 0.36-\frac{Q(t)}{1000} \\=\frac{360-Q(t)}{1000}

Separate the variables and integrate

\frac{1000dQ}{360-q(t)} =dt\\-1000 ln |360-Q(t)| = t+C\\ln |360-Q(t)| = -0.001+C'\\360-Q(t) = Ae^{-0.001t} \\Q(t) = 360-Ae^{-0.001t}

Use the fact that Q(0) = 90

90 = 360-A

A = 270

So

Q(t) = 360-270e^{-0.001t}

B) Q(t) = 360-270e^-0.004  = 91.07784

C) When t approaches infinity, we get

Q(t) tends to 360

So concentration =360/1000 = 0.36

8 0
3 years ago
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