Answer:

Step-by-step explanation:
<u>The full question:</u>
<em>"A committee has eleven members. there are 3 members that currently serve as the boards chairman, ranking members, and treasurer. each member is equally likely to serve in any of the positions. Three members are randomly selected and assigned to be the new chairman, ranking member, and treasurer. What is the probability of randomly selecting the three members who currently hold the positions of chairman, ranking member, and treasurer and reassigning them to their current positions?"</em>
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The permutation of choosing 3 members from a group of 11 would be:
P(n,r) = 
Where n would be the total [in this case n is 11] & r would be 3
Which is:
P(11,3) = 
So there are total of 990 possible way and there is ONLY ONE WAY for them to be reassigned. Hence the probability would be:
1/990
Answer:
32+d
Step-by-step explanation:
because it's asking for 32 added on to whatever d is
example
if d=5 it would be asking what's 32 +5
Nothing crazy here, just a matter of figuring out the limits of integration.



Answer:
4.
Step-by-step explanation:
There are 18 squares, if you want to shade 2/9 you have to make the denominator, which is 9 into 18, so you multiply by 2, you will do the same thing to the numerator, 2x2=4 9x2=18.
Brainiest would be appreciated.
Step-by-step explanation:
i think this is the answer if its wrong im sorry