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Leno4ka [110]
3 years ago
8

HELP ME PLEASE ASAP IM FAIL MATH

Mathematics
2 answers:
katrin2010 [14]3 years ago
7 0

Ommgggg I’m failing too twins

olga2289 [7]3 years ago
4 0
OMG SAME!!!!!!!!!!!!!!!!!
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Where was a error made in combining and solving the equation below?
Lera25 [3.4K]
It should be a positive 5 not a negative so the error was made at the end because u divide
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NEED HELP ASAP!!!
azamat
The answer is B f(x)= -3(x+1)^2+2
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Life Expectancies In a study of the life expectancy of people in a certain geographic region, the mean age at death was years an
Sphinxa [80]

Answer:

The probability that the mean life expectancy of the sample is less than X years is the p-value of Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}, in which \mu is the mean life expectancy, \sigma is the standard deviation and n is the size of the sample.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

We have:

Mean \mu, standard deviation \sigma.

Sample of size n:

This means that the z-score is now, by the Central Limit Theorem:

Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

Find the probability that the mean life expectancy will be less than years.

The probability that the mean life expectancy of the sample is less than X years is the p-value of Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}, in which \mu is the mean life expectancy, \sigma is the standard deviation and n is the size of the sample.

8 0
2 years ago
Find the area of the figure. Use 3.14 for A.
Masteriza [31]

Answer:

38.13 m^2

Step-by-step explanation:

the area of a triangle =b*h/2

b=base

h=height

area triangle=(4m*3m)/2=(12m^2)/2=6m^2

the area of a rectangle =b*h

b=base

h=height

area of a rectangle=6m*3m=18m^2

area of a semi circle=(pi*r^2)/2

r=radius

area of a semi circle==(3.14*(3m)^2)/2=14.13m^2

area of the figure=6m^2+18m^2+14.13m^2=38.13m^2

the answer is 38.13m^2

8 0
3 years ago
HOW MANY TIMES DOES 8 GOES INTO 12
spin [16.1K]
It goes in 1 and 1/2 times. You can solve this by dividing 12 by 8
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