Plzzzz hurry test worth 25 points. Will mark as brainliest and don't mess around and answer correctly plzzz. The figure below sh
ows parallel lines cut by a transversal:
Which statement is true about ∠7 and ∠8? (4 points)
A. ∠7 and ∠8 are supplementary because they are a pair of corresponding angles.
B. ∠7 and ∠8 are complementary because they are a pair of adjacent angles on a straight line.
C. ∠7 and ∠8 are congruent because they are a pair of adjacent angles on a straight line.
D. ∠7 and ∠8 are supplementary because they are a pair of adjacent angles that form a straight line.
Which statement is true about ∠7 and ∠8? (4 points)
A. ∠7 and ∠8 are supplementary because they are a pair of corresponding angles.
B. ∠7 and ∠8 are complementary because they are a pair of adjacent angles on a straight line.
C. ∠7 and ∠8 are congruent because they are a pair of adjacent angles on a straight line.
D. ∠7 and ∠8 are supplementary because they are a pair of adjacent angles that form a straight line.
2 answers:
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Hello once again!
When you see a question like this, you need to find the equation of the straight line.
The formular used is y = mx + c
Where
m = slope
c = constant
First find the slope, since it's a straight line, any 2 coordinates can be used.
Now we need to substitude in the slope, and one of the coordinate you used to find the slope, to the formular to find the constant.
In this case i'm using the coordinate
(-2, 16)
y = mx + c
16 = -6(-2) + c
16 = 12 + c
c = 4
∴ The equation of the line is y = -6x + 4
The next step is to simply substitude in the x = 8 to the equation to find y.
y = -6(8) + 4
y = -48 + 4
y = -44
When you see a question like this, you need to find the equation of the straight line.
The formular used is y = mx + c
Where
m = slope
c = constant
First find the slope, since it's a straight line, any 2 coordinates can be used.
Now we need to substitude in the slope, and one of the coordinate you used to find the slope, to the formular to find the constant.
In this case i'm using the coordinate
(-2, 16)
y = mx + c
16 = -6(-2) + c
16 = 12 + c
c = 4
∴ The equation of the line is y = -6x + 4
The next step is to simply substitude in the x = 8 to the equation to find y.
y = -6(8) + 4
y = -48 + 4
y = -44