1. One quater and one nicle 2. Three Dimes 3. 6 nickels 4. One dime and four nickles 5. two nickles and two dimes i think
Answer:
step 1
Find the average growth per year of the populations of rabbits farm A
Over the first 2 years
for t=0
numbers of rabbits=5 (is not exact)
for t=2
numbers of rabbits=40
average=[40-5]/2---------> 17.5
step 2
Find the average growth per year of the populations of rabbits farm B
Over the first 2 years
for t=0
numbers of rabbits=5 (is not exact)
for t=2
numbers of rabbits=30
average=[30-5]/2---------> 12.5
step 3
Compare the average growth per year of the populations of rabbits on both farms
farm A=17.5
farm B=12.5
the average rate of population growth of rabbits in farm A is greater than average rate of population growth of rabbits in farm B by about 5 rabbits per year.
therefore
the answer is the option C)
the average rate of population growth of rabbits in farm A is greater than average rate of population growth of rabbits in farm B by about 6 rabbits per year.
Step-by-step explanation:
X+y= -12
xy=8
y=8/x
x+8/x=-12
x^2+12x+8=0
This has no integral
You add the exponents together when multiplying
no it's 22 :D...............
