We know that
The MAD is the mean absolute deviation of the data

step 1
To find the mean absolute deviation of the data, start by finding the mean of the data set.
Find the sum of the data values, and divide the sum by the number of data values
sum of the data values=[130+150+190+100+175+120+165+140+180+190]
sum of the data values=1540
number of data=10
Mean=1540/10-----> 154

step 2
Find the absolute value of the difference between each data value and the mean: |data value – mean|.
 |130 – 154|=24
|150 – 154|=4
|190 – 154|=44
|100 – 154|=54
|175 – 154|=21
|120 – 154|=34
|165 – 154|=11
|140 – 154|=14
|180 – 154|=26
|190 – 154|=44

step 3
Find the sum of the absolute values of the differences.
=[24+4+44+54+21+34+11+14+26+44]------> 276

step 4
Divide the sum of the absolute values of the differences by the number of data values.
276/10-----> 27.6

the answer is
27.6

5 0

3 years ago

Three less than one-fourth of the product of eight thirds and nine. Please write equation, then solve.

kenny6666 [7]

Put simply, you have to work backwards in making the equations. Start with the product of 8/3 and 9.
$\frac{8}{3}$ *9

Next take 1/4 of that. This can be done in two ways, either multiplying by 1/4:
( $\frac{8}{3}$ *9)* $\frac{1}{4}$

, or dividing everything by 4.
( $\frac{8}{3}$ *9)/4

Finally, subtract three.

The final equation would read:
(( $\frac{8}{3}$ *9)* $\frac{1}{4}$ )-3

Using PE(M/D)(A/S), we'd start with $\frac{8}{3}$ *9

3 and 9 cancel out to be 1 and 3, leaving us with $\frac{8}{1}$ , or 8, and 3 and this part of the equation reading 8*3, which is 24.

The next step is $\frac{24}{4}$ , which is 6.

Lastly we subtract 3 from six, leaving us 3.

7 0

3 years ago

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