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2 years ago

5

Which of the following is true? there is a phase shift to the left. there is a phase shift to the right. the graph is reflected

across the x-axis the graph is stretched horizontally. the graph is compressed horizontally.

1 answer:

sammy [17]2 years ago

7 0

Answer:

a. There is a phase shift to the left

Step-by-step explanation:

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Last math question.

siniylev [52]

Answer:

<h2>y = 5x + 11</h2>

Step-by-step explanation:

$\text{The slope-intercept form of an equation of a line:}\\\\y=mx+b\\\\m-\text{slope}\\b-\text{y-intercept}\\\\\text{Let}\\\\k:y=m_1x+b_1\\l:y=m_2x+b_2\\\\k\ \perp\ l\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\\\k\ ||\ l\iff m_1=m_2\\=========================$

$\text{We have}\ y=5x+2\to m_1=5\\\\\text{therefore}\ m_2=5.\\\\\text{Put the value of the slope and the coordinates of the given point (-2, 1)}\\\text{to the equation of a line:}\\\\1=5(-2)+b\\1=-10+b\qquad\text{add 10 to both sides}\\1+10=-10+10+b\\11=b\to b=11\\\\\text{Finally:}\\\\y=5x+11$

5 0

4 years ago

Write a kinda short song about 1 polygon with a familiar tune

STALIN [3.7K]

A triangle is A polygon with 3 angles(x2) 3 sides

3 0

3 years ago

A student on a piano stool rotates freely with an angular speed of 2.85 rev/s . The student holds a 1.50 kg mass in each outstre

Vlad1618 [11]

Answer:r'=0.327 m

Step-by-step explanation:

Given

$N=2.85 rev/s$

angular velocity $\omega =2\pi N=17.90 rad/s$

mass of objects $m=1.5 kg$

distance of objects from stool $r_1=0.789 m$

Combined moment of inertia of stool and student $=5.53 kg.m^2$

Now student pull off his hands so as to increase its speed to 3.60 rev/s

$\omega _2=2\pi N_2$

$\omega _2=2\pi 3.6=22.62 rad/s$

Initial moment of inertia of two masses $I_0=2mr_^2$

$I_0=2\times 1.5\times (0.789)^2=1.867$

After Pulling off hands so that r' is the distance of masses from stool

$I_0'=2\times 1.5\times (r')^2$

Conserving angular momentum

$I_1\omega =I_2\omega _2$

$(5.53+1.867)\cdot 17.90=(5.53+I_o')\cdot 22.62$

$I_0'=1.397\times 0.791$

$I_0'=5.851$

$5.53+2\times 1.5\times (r')^2=5.851$

$2\times 1.5\times (r')^2=0.321$

$r'^2=0.107009$

$r'=0.327 m$

7 0

3 years ago

tigry1 [53]

This most definitely has to be a rhombus since it is a form of a square with 4 congruent sides where a rectangle only has 4 right angles.
To clarify, a trapezoid only has one pair of parallel sides if you were wondering.

8 0

4 years ago

What is negative 7/10 minus 2/5

Dmitriy789 [7]

The answer you are looking for is -11/10 or - 1 1/10.

To find this answer you must first make the denominators the same. To do this, multiply 2/5 by 2/2 to get 4/10. Finally, subtract the two fractions, keeping in mind the denominators stay the same. -7/10 - 4/10 = -11/10 or - 1 1/10.

I hope this helps!

4 0

4 years ago