Answer:
Option (4). y = 3x - 5
Step-by-step explanation:
Given question is incomplete; here is the complete question.
What is the equation of the line that is perpendicular to the given line and passes through the point (3, 4)?
y = –1/3x + 5
y = –1/3x + 3
y = 3x + 2
y = 3x − 5
Line given in the graph passes through the points (-3, 2) and (0, 1).
Slope of the given line = 
m = 
m = 
Let the equation of a line perpendicular to this line is,
y - y' = m'(x - x') [Given line passes through (x', y')]
By the property of perpendicular lines,
m × m' = -1
(
) × m' = -1
m' = 3
Equation of the perpendicular line will be,
y - 4 = 3(x - 3)
y - 4 = 3x - 9
y = 3x - 5
Option (4) will be the answer.
Answer:
x = - 6.22 or - 56/9
Step-by-step explanation:
Step 1:
34 + 12x = 3x - 22 Equation
Step 2:
12x = 3x - 56 Subtract 34 on both sides
Step 3:
9x = - 56 Subtract 3x on both sides
Step 4:
x = - 56 ÷ 9 Divide
Answer:
x = - 6.22
Hope This Helps :)
Equation 1 : x + y + z = 3.25
equation 2 : 12x + 2y + z = 9.50
equation 3 : 2x + 4y + 5z = ??
u would multiply equation 1 by -12.....take that result and add it to equation 2....this eliminates x.
u would multiply equation 3 by -6...take that result and add it to equation 2....this eliminates x
Answer:
lim
x->3. 3×(3) Sq. -4×3-15
------------------------
(3) Sq. +3-12
lim
x->3. 3×9-12-15
---------------
9+3-12
lim
x->3. 0/0(which is in determinant form)
The answer is c to your problemo