3(x+2)+11>20
minus 11 both sides
3(x+2)>9
divide both sides by 3
x+2>3
minus 2 both sides
x>1
The formula of the length of the segment AB:

We have:

Substitute:

Answer:
B) 10.
SA = Ph + 2B. Solve for h.
To solve for h, you need to isolate it.
First step is to subtract 2B from both sides:
SA - 2B = Ph
Now divide both sides by P:
h = (SA - 2B) / P